SetInterval函数调用 [英] SetInterval function calls
问题描述
< script>
setInterval(function1,3000);
setInterval(function2(),3000);
function function1(){
console.log(Function1 called ....);
function function2(){
console.log(Function2 called ....);
}
< / script>
正如你所看到的,我有两个 setInterval
函数调用函数如 function1
和另一个 function2()
。第一个输出是完美的,每3秒调用一次,3秒后首先调用。但是第二个被调用没有延迟,即 function2
。
我想 setInterval $ c $中有
c>您正在执行它并将该函数返回的值插入 setInterval
。
例如,
setInterval(a(),5000);
函数a(){
返回函数(){
console.log(Executed!);
};
};
a()
执行并返回函数
到 setInterval
中。你应该看到控制台每5秒钟写入 Executed
。
这就像数学:
(2)$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ )= g(x)+ 2 = 4
将g(2)替换为任何它返回的
(在这种情况下用函数替换一个())
http:// jsfiddle。 net / DerekL / 39wNn /
I am getting into sort of confusion here. Please go through the below code,
<script>
setInterval(function1,3000);
setInterval(function2(),3000);
function function1() {
console.log("Function1 called....");
}
function function2() {
console.log("Function2 called....");
}
</script>
As you can see I have two setInterval
functions one calls function like function1
and another function2()
. The output of first is perfect that gets called every 3sec and first call after 3sec. But second one gets called without the delay i.e function2
.
I guess that ()
might be doing things there but I'm not sure about what I'm missing there. I just want to know what is happening there.
In the second setInterval
you are executing it right away and plugging the value returned by that function into setInterval
.
For example,
setInterval(a(), 5000);
function a(){
return function(){
console.log("Executed!");
};
};
a()
executed and returning the function
into setInterval
. You should see the console is writing Executed
every 5 seconds.
This is just like math:
f(x) = x + 1
g(x) = 2
f(g(2)) = g(x) + 2 = 4
You replace g(2) with whatever it returns
(you replace a() with the function in this case)
http://jsfiddle.net/DerekL/39wNn/
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