'（'用于函数样式转换或构造类型的Xcode错误 [英] '(' for function-style cast or construction type Xcode error
问题描述
calcScore（double score1，double score2，double score3，double score4，double score5）;
这里是我的代码，我不知道如何解决错误;我不确定错误的含义。我试过在教科书和网上看例子，但我仍然感到困惑;这是我们必须使用函数的第一个任务
#include< iostream>
使用namespace std;
void getJudgesData（）;
void calcScore（）;
int main（）
{
double scoreAverage = -9;
double score1 = -9.0;
double score2 = -9.0;
double score3 = -9.0;
double score4 = -9.0;
double score5 = -9.0;
getJudgesData（）;
calcScore（双倍1，双倍2，双倍3，双倍4，双倍5）;
返回0;
}
// getJudgesData程序
void getJudgesData（double& score1，double& score2，double& score3，double& score4，double& score5）
{
do
{
cout<< 输入法官评分：;
cin>> score1;
do
{
if（score1 <0 || score1> 10）
{
cout<< 得分范围从0-10 \\\
;
cout<< 请输入有效分数：;
cin>> score1;
}
} while（score1< 0 || score1> 10）;
}
while（score1 <0 || score1> 10）;
do
{
cout<< 输入法官评分：;
cin>> score2;
do
{
if（score2 <0 || score2> 10）
{
cout< 得分范围从0-10 \\\
;
cout<< 请输入有效分数：;
cin>> score2;
}
} while（score2 <0 || score2> 10）;
}
while（score2 <0 || score2> 10）;
do
{
cout<< 输入法官评分：;
cin>> score3;
do
{
if（score3 <0 || score3> 10）
{
cout<< 得分范围从0-10 \\\
;
cout<< 请输入有效分数：;
cin>> score3;
}
} while（score3 <0 || score3> 10）;
}
while（score3 <0 || score3> 10）;
do
{
cout<< 输入法官评分：;
cin>> score4;
do
{
if（score4 <0 || score4> 10）
{
cout<< 得分范围从0-10 \\\
;
cout<< 请输入有效分数：;
cin>> score4;
}
} while（score4< 0 || score4> 10）;
}
while（score4 <0 || score4> 10）;
do
{
cout<< 输入法官评分：;
cin>> score5;
do
{
if（score5 <0 || score5> 10）
{
cout<< 得分范围从0-10 \\\
;
cout<< 请输入有效分数：;
cin>> score5;
}
} while（score5 <0 || score5> 10）;
}
，（分数5 <0 ||分数5> 10）;
return;
}
// calcScore开始
void calcScore（双分1，双分2，双分3，双分4，双分5）
{
double平均;
average =（score1 + score2 + score3 + score4 + score5）/ 5;
return;
}
让我们首先处理您的错误：正如@ shree.pat18在评论中指出的那样，你正在调用一个函数并试图给出参数的类型。这是不允许的。 C ++ 知道参数的类型，因为您之前已声明了它们。您可以像这样调用 calcScore ：
double score1 = -9.0;
double score2 = -9.0;
double score3 = -9.0;
double score4 = -9.0;
double score5 = -9.0;
getJudgesData（）;
calcScore（得分1，得分2，得分3，得分4，得分5）;
然而，这会带来一个新问题：在编译时，编译器不会了解一个名为 calcScore 的函数，该函数需要5个 double 类型的参数。
您声明了两个名为 calcScore 的函数：一个是简单声明的，没有定义参数，另一个声明和定义参数：
//只是一个声明。此函数没有定义，并且不会链接
void calcScore（）;
和
//声明和定义
void calcScore（双分1，双分2，双分3，双分4，双分5）
{
}
您可以删除第一个 calcScore 的声明，因为我假设您不需要，并将其更改为：
void calcScore（double score1，double score2，double score3，double score4，double score5）;
现在当您尝试调用 calcScore 和在你的 main 中传入5 double ，编译器会知道你指的是什么函数。
This is where I get error:
calcScore(double score1,double score2, double score3, double score4, double score5);
here is the my code, I do not know how to fix the error; I am not sure what the error means. I've tried looking at examples in textbook, and online but I am still confused; this is first assignment where we have to use function
#include <iostream>
using namespace std;
void getJudgesData();
void calcScore();
int main()
{
double scoreAverage=-9;
double score1=-9.0;
double score2=-9.0;
double score3=-9.0;
double score4=-9.0;
double score5=-9.0;
getJudgesData();
calcScore(double score1,double score2, double score3, double score4, double score5);
return 0;
}
// getJudgesData Program
void getJudgesData(double &score1, double &score2, double &score3, double &score4, double &score5)
{
do
{
cout << "Enter judges score: ";
cin >> score1;
do
{
if (score1 < 0 || score1 >10)
{
cout << "Score has to range from 0-10 \n";
cout << "Please enter a valid score: ";
cin >> score1;
}
}while (score1<0 || score1 >10);
}
while (score1<0 || score1 >10);
do
{
cout << "Enter judges score: ";
cin >> score2;
do
{
if (score2 < 0 || score2 >10)
{
cout << "Score has to range from 0-10 \n";
cout<< "Please enter a valid score: ";
cin >> score2;
}
}while (score2 <0 || score2 >10);
}
while (score2<0 || score2 >10);
do
{
cout << "Enter judges score: ";
cin >> score3;
do
{
if (score3 < 0 || score3 >10)
{
cout << "Score has to range from 0-10 \n";
cout << "Please enter a valid score: ";
cin >> score3;
}
}while (score3 < 0 || score3 >10);
}
while (score3<0 || score3 >10);
do
{
cout << "Enter judges score: ";
cin >> score4;
do
{
if (score4 < 0 || score4 >10)
{
cout << "Score has to range from 0-10 \n";
cout << "Please enter a valid score: ";
cin >> score4;
}
}while (score4 < 0 || score4 >10);
}
while (score4<0 || score4 >10);
do
{
cout << "Enter judges score: ";
cin >> score5;
do
{
if (score5 < 0 || score5 >10)
{
cout << "Score has to range from 0-10 \n";
cout << "Please enter a valid score: ";
cin >> score5;
}
}while (score5 < 0 || score5 >10);
}
while (score5<0 || score5 >10);
return;
}
//Start of calcScore
void calcScore( double score1, double score2, double score3, double score4,double score5)
{
double average;
average = (score1+score2+score3+score4+score5)/ 5;
return;
}
Let's deal with your error first: as @shree.pat18 points out in the comments, you are calling a function and trying to give the type of the parameters. This isn't allowed. C++ knows the type of the parameters because you declared them previously. You can call calcScore like so:
double score1=-9.0;
double score2=-9.0;
double score3=-9.0;
double score4=-9.0;
double score5=-9.0;
getJudgesData();
calcScore(score1, score2, score3, score4, score5);
However, that brings you to a new problem: At the time of compilation, the compiler doesn't know about a function called calcScore which takes 5 parameters of type double.
You are declaring two functions called calcScore: one is simply declared and not defined with no parameters, and the other is declared and defined with parameters:
// just a declaration. This function has no definition and will not link
void calcScore();
and
// declared and defined
void calcScore( double score1, double score2, double score3, double score4,double score5)
{
}
You can remove the first declaration of calcScore since I assume you don't need both, and change it to be:
void calcScore(double score1, double score2, double score3, double score4, double score5);
Now when you try to invoke calcScore and pass in 5 double within your main, the compiler will know what function you are referring to.
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