“gcc -s”与“gcc -s”是什么区别？和“条”命令？ [英] What is the difference between "gcc -s" and a "strip" command?

问题描述

我想知道这两者之间有什么区别：

• gcc -s ：从可执行文件中删除所有符号表和重定位信息。




• strip ：Discard
  
  
  

  它们具有相同的含义吗？

  
  
  

  您使用哪一个：
  $ b

  
  
  • 减少可执行文件的大小？
  
  
  • 加速运行？
  code> gcc 是一个编译器/链接器，它的 -s 选项是在编译和链接时完成的 。它也是不可配置的 - 它有一组信息，它被删除，不多不少。
  
  

  strip 是可以在已编译的目标文件上运行的东西。它还具有各种命令行选项，您可以使用它们来配置哪些信息将被删除。例如， -g 仅剥离 gcc -g 添加的调试信息。

  
  
  

  请注意， strip 不是bash命令，尽管您可能正在从bash shell运行它。它是一个完全独立于bash的命令，是GNU二进制工具套件的一部分。

  
  

  I wonder what is the difference between these two:

  • gcc -s: Remove all symbol table and relocation information from the executable.

  • strip: Discard symbols from object files.

  Do they have the same meaning?

  Which one do you use to:

  • reduce the size of executable?
  • speed up its running?

  解决方案

  gcc being a compiler/linker, its -s option is something done while compiling and linking. It's also not configurable - it has a set of information which it removes, no more no less.

  strip is something which can be run on an object file which is already compiled. It also has a variety of command-line options which you can use to configure which information will be removed. For example, -g strips only the debug information which gcc -g adds.

  Note that strip is not a bash command, though you may be running it from a bash shell. It is a command totally separate from bash, part of the GNU binary utilities suite.

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