GCC声明表达问题 [英] GCC Statement Expression Issue
问题描述
请注意这个例子:
#include< stdio.h>
int main(void)
{
char * res1 =({
char arr [] = {'h','e', '\0'}; //是char * arr []
arr [0] ='x';
char * ptr = arr;
ptr;
}) ;
$ b $ char * res2 =({
char arr [] = {'h','e','\0'}; //是char * arr [ ]
arr [0] ='X';
char * ptr = arr;
ptr;
});
printf(%s%p\\\
,res1,res1);
printf(%s%p\\\
,res2,res2);
返回0;
}
输出:
X 0x7fff93098160
X 0x7fff93098160
我注意到,第一个块中的变量 arr
,第二个块中的变量 arr
取得相同的内存地址。
为什么会发生这种情况?
arr
是具有自动存储持续时间的数组对象;它们是语句表达式中的 {...}
封闭块的本地语句。
该局部变量的地址;该地址保存在 res1
和res2 中,并在块结束后使用*,当对象
arr` 。这个地址在变量不存在时变为无效,程序的行为是未定义的。
所以不要那样做。
I just read about Statement Expressions Extension in GCC, and I found some unexpected behavior when using it.
Please observe this example:
#include <stdio.h>
int main(void)
{
char* res1 = ({
char arr[] ={'h', 'e', '\0'}; // was char *arr[]
arr[0] = 'x';
char* ptr = arr;
ptr;
});
char* res2 = ({
char arr[] ={'h', 'e', '\0'}; // was char *arr[]
arr[0] = 'X';
char* ptr = arr;
ptr;
});
printf ("%s %p\n", res1, res1);
printf ("%s %p\n", res2, res2);
return 0;
}
Output:
X 0x7fff93098160
X 0x7fff93098160
I noticing that, the variables arr
in first block and arr
in second block taking the same memory address.
Why that happening??
Both occurrences of arr
are array objects with automatic storage duration; they're local to the enclosing block { ... }
within the statement expression.
Each statement expression grabs the address of that local variable; that address is saved in res1
and res2and used *after* the end of the block, when the object
arr` no longer exists.
This is the same problem as a function returning the address of a local variable. The address becomes invalid when the variable ceases to exist, and the program's behavior is undefined.
So don't do that.
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