代码用g ++编译而不是gcc [英] code compiles with g++ but not gcc

问题描述

下面这段代码用g ++编译而不是gcc，并且我想知道为什么？

The following piece of code compiles with g++ and not gcc, and am stuck wondering why?

inline unsigned FloatFlip(unsigned f)
{
    unsigned mask = -int(f >> 31) | 0x80000000;
    return f ^ mask;
}

我假设在C ++中，
int（f >> 31）
是一个构造函数，但这让我想知道为什么它包含在代码中。是否有必要？

I would assume that in C++, int(f >> 31) is a constructor but that leaves me wondering why its included in the code.Is it necessary?

推荐答案

C不支持C ++函数式转换。你需要像这样写

C doesn't support the C++ "function-style" casting. You need to write it like this

unsigned mask = -(int)(f >> 31) | 0x80000000;

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