从旧的+ n米计算新的经度，纬度 [英] Calculating new longitude, latitude from old + n meters

问题描述

我想创建2个新的经度和2个新的纬度，基于一个坐标和一个以米为单位的距离，我想围绕某个点创建一个漂亮的边界框。其小规模，最大1500米+和1500米 - 。因此，这是一个城市的一部分，我不认为地球的曲线必须考虑。

所以我有50.0452345（x）和4.3242234（y）我想知道x + 500meter，x-500meter，y-500meter，y + 500meter

我发现了很多算法，但几乎所有算法似乎都处理点之间的距离。

解决方案

每度经度的公里数大约是

 （2 * pi / 360）* r_earth * cos（theta）
  

其中 theta 是以度数表示的纬度，而 r_earth 约为6378 km。

所有地点的每度纬度公里数大致相同，约

 （2 * pi / 360）* r_earth = 111 km / degree 
  

所以你可以做：

  new_latitude =纬度+（dy / r_earth）*（180 / pi）; 
 new_longitude =经度+（dx / r_earth）*（180 / pi）/ cos（纬度* pi / 180）; 
  

只要 dx 和 dy 与地球半径相比较小，并且不会太接近极点。

I want to create 2 new longitude and 2 new latitudes based on a coordinate and a distance in meters, I want to create a nice bounding box around a certain point. Its small scale and max 1500meters + and 1500meter -. So it is for a part of a city, I don't think the curve of the earth has to be taken into account.

So I have 50.0452345(x) and 4.3242234(y) and I want to know x+500meter, x-500meter, y-500meter, y+500meter

I found many algorithms but almost all seem to deal with the distance between points.

解决方案

The number of kilometers per degree of longitude is approximately

(2*pi/360) * r_earth * cos(theta)

where theta is the latitude in degrees and r_earth is approximately 6378 km.

The number of kilometers per degree of latitude is approximately the same at all locations, approx

(2*pi/360) * r_earth = 111 km / degree 

So you can do:

new_latitude  = latitude  + (dy / r_earth) * (180 / pi);
new_longitude = longitude + (dx / r_earth) * (180 / pi) / cos(latitude * pi/180);

As long as dx and dy are small compared to the radius of the earth and you don't get too close to the poles.

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