计算新的经度，纬度从旧+ N米 [英] Calculating new longtitude, latitude from old + n meters

问题描述

我试图寻找这件事，但我不能在任何地方找到它：

I tried looking this up but I cant find it anywhere:

我要创建2个新的经度和2个基于一个坐标和在米的距离新的纬度，我想创建一个围绕某一个点一个漂亮的边框。它的规模小，最大1500米+和1500米 - 。所以它是一个城市的一部分，我不认为地球的曲线，必须考虑到。

I want to create 2 new longtitude and 2 new latitudes based on a coordinate and a distance in meters, I want to create a nice bounding box around a certain point. Its small scale and max 1500meters + and 1500meter -. So it is for a part of a city, I dont think the curve of the earth has to be taken into account.

所以，我有50.0452345（x）和4.3242234（Y），我想知道X +500米，X500米，Y-500米，Y +500米

So I have 50.0452345(x) and 4.3242234(y) and I want to know x+500meter, x-500meter, y-500meter, y+500meter

我发现有很多算法，但是几乎所有的似乎处理点之间的距离。

I found many algorithms but almost all seem to deal with the distance between points.

推荐答案

每经度程度公里​​数大约

The number of kilometers per degree of longitude is approximately

(2*pi/360) * r_earth * cos(theta)

其中， THETA 为度纬度和 r_earth 大约6378公里。

where theta is the latitude in degrees and r_earth is approximately 6378 km.

的每纬度的度数公里数大约相同，在所有位置，约

The number of kilometers per degree of latitude is approximately the same at all locations, approx

(2*pi/360) * r_earth = 111 km / degree 

所以，你可以这样做：

So you can do:

new_latitude  = latitude  + (dy / r_earth) * (180 / pi);
new_longitude = longitude + (dx / r_earth) * (180 / pi) / cos(latitude * pi/180);

只要 DX 和 DY 小比地球的半径，你没有得到太靠近磁极

As long as dx and dy are small compared to the radius of the earth and you don't get too close to the poles.

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