确定多个点的质心 [英] Determine the centroid of multiple points

问题描述

我在写一个映射应用程序，我正在用python编写，我需要获得N个点的纬度/经度质心。
说我有两个地点

I'm writing a mapping application that I am writing in python and I need to get the lat/lon centroid of N points. Say I have two locations

a.lat = 101
a.lon = 230

b.lat = 146
b.lon = 200

使用欧几里得公式很容易得到两点的中心点。我希望
能够做到更多两分。

Getting the center of two points is fairly easy using a euclidean formula. I would like to be able to do it for more then two points.

基本上，我正在寻找像 http://a.placebetween.us/ ，可以输入多个地址并找到每个人都等距的地点。

Fundamentally I'm looking to do something like http://a.placebetween.us/ where one can enter multiple addresses and find a the spot that is equidistant for everyone.

推荐答案

查看下面链接的pdf文档。它解释了如何应用比尔蜥蜴提到的平面图算法，但在球体表面。

Have a look at the pdf document linked below. It explains how to apply the plane figure algorithm that Bill the Lizard mentions, but on the surface of a sphere.

海报缩略图和一些细节http://img51.imageshack.us/img51/4093/centroidspostersummary.jpg

来源： http://www.jennessent.com/arcgis/shapes_poster.htm

还有一个 25 MB全尺寸PDF 可供下载。

Credit to <一个href =https://stackoverflow.com/users/6109/mixdev> mixdev 用于查找原始来源的链接，当然还有Jenness Enterprises提供的信息。注意：我与这篇文章的作者没有任何关系。

poster thumbnail and some details http://img51.imageshack.us/img51/4093/centroidspostersummary.jpg
Source: http://www.jennessent.com/arcgis/shapes_poster.htm
There is also a 25 MB full-size PDF available for download.
Credit goes to mixdev for finding the link to the original source, and of course to Jenness Enterprises for making the information available. Note: I am in no way affiliated with the author of this material.

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