从字符串中提取数字？ Java的 [英] Extract numbers from a string?! Java

问题描述

对于我的程序，我正在尝试着想如何才能让用户输入一串数字作为字符串;提取每个数字的空格并将它们解析为整数。

PS我仍然是编程语言的新手，所以请以我能理解的方式解释，谢谢。 / p>

这是我到目前为止：

用户可以输入一系列数字，例如：15 31 94 87 108 11 7 63 79

  public int [] getNumbers（）{
 
扫描器读取器=新的扫描仪（System.in）; 
 
 String inputStr = reader.nextLine（）; 
 
 int [] a = new int [10]; 
 String [] numb = new String [10]; 
 
 int space = inputStr.indexOf（）; 
 int length = inputStr.length（）; 
 
 for（int x = 0; x  
 numb [x] = inputStr.substring（0，space）; 
 inputStr = inputStr.substring（space + 1）; 
 
 int num = Integer.parseInt（numb [x]）; 
 System.out.println（num）; 
 a [x] = num; 
} 
 return a; 
} 
  

此时获取第一个数字，然后缩短字符串。我将如何去寻找下一个数字，并结束它，因为它出界了？谢谢。

解决方案

您可以使用字符串的拆分方法来完成此操作：

  String [] numbers = numb.split（）; 
 int [] a = new int [numbers.length]; 
 
 for（int x = 0; x  a [x] = Integer.parseInt（numbers [x]）;; 
} 
  

For my program I am trying to figure how I can go about taking a series of number as string entered by the user; extract each number at spaces and parse them into integers.

P.S I am still a newbie to the programming languages so please explain in a way that I can understand, thanks.

This is what I have so far:

A user may input a series of number like this: 15 31 94 87 108 11 7 63 79

public int [] getNumbers (){

    Scanner reader = new Scanner (System.in);

    String inputStr = reader.nextLine();

    int[] a = new int [10];
    String[] numb = new String [10];

    int space = inputStr.indexOf (" ");
    int length = inputStr.length(); 

    for (int x = 0; x < numb.length; x++){

        numb [x] = inputStr.substring (0, space); 
        inputStr = inputStr.substring (space+1);

        int num = Integer.parseInt (numb[x]);
        System.out.println (num);
        a[x] = num;
    }
    return a;
}

This at the moment get the first number, then shorten the string. How would I go about finding the next number and ending it with out having it going out of bound ? thank you.

解决方案

You can do this using string's split method:

String[] numbers = numb.split(" ");
int[] a = new int [numbers.length];

for (int x = 0; x < numb.length; x++){
        a[x] = Integer.parseInt (numbers[x]);;
}

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