java中的HTTP GET请求 [英] HTTP GET request in java

问题描述

我试图在java上使用http获取请求，将端口号为4567的本地主机发送给我。
我得到了请求：wget -q -O- http：// localhost：4567 / XXXX
[XXXX是一些参数 - 不相关]。
我发现了一个java库java.net.URLConnection用于这些类型的事情，但似乎URLConnection对象应该接收url / port / ..和所有其他类型的参数（换句话说，你必须自己构建对象），但是，我得到了完整的http请求，就像我上面写的那样。有没有办法简单地'射击'请求而不处理为URLConnection构建字段？

I'm trying to use http get request on java, to my localhost on port number 4567. I got the get request: "wget -q -O- http://localhost:4567/XXXX" [XXXX is some parameter - not relevent]. I've found a java library java.net.URLConnection for these kind of things but it seems that the URLConnection object is supposed to receive the url/port/.. and all other kind of parameters (In other words, you have to construct the object yourself), however, I got the full http get request as I've written above. Is there a way to simply 'shoot' the request without dealing with constructing the field for URLConnection?

推荐答案

您可以创建 URL 对象使用你的URL，它会自己计算出端口和其他东西。参考： https://docs.oracle.com/javase/tutorial/networking /urls/readingWriting.html

You can create the URL object using your URL, it will figure out ports and other things itself. Ref : https://docs.oracle.com/javase/tutorial/networking/urls/readingWriting.html

public class URLConnectionReader {
    public static void main(String[] args) throws Exception {
        URL oracle = new URL("http://localhost:4567/XXXX");
        URLConnection yc = oracle.openConnection();
        BufferedReader in = new BufferedReader(new InputStreamReader(
                                    yc.getInputStream()));
        String inputLine;
        while ((inputLine = in.readLine()) != null) 
            System.out.println(inputLine);
        in.close();
    }
}

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