R:在同一个boxplot图上绘制一条线 [英] R: draw a line on the same boxplot graph
本文介绍了R:在同一个boxplot图上绘制一条线的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这段代码很好用:
x < - c(91,92,93,125,123,140)
y <-c(200,260,220,300,350,360)
d1 < - data.frame (x = x,y = y)
d1 $ f1 =因子(round(d1 $ x / 10))
qplot(f1,y,data = d1,geom =boxplot)
d2 <-data.frame(x2 = c(90,140),y2 = c(210,320))
qplot(x2,y2,data = d2,geom =line)
但是当我尝试将该行添加到图表中时...
<$
>
qplot(f1,y,data = d1,geom =boxplot)+ geom_line(data = d2,aes(x = x2,y = y2))
查看我的结果: http://jeb-files.s3.amazonaws.com/Clipboard01.jpg
我如何设法让我的在线对齐我的boxplot?
谢谢!
解决方案 code> boxplot
要求x值是因素,whe重新设置 geom_line
要求x值为数字。你可以通过修改 geom_line
调用来获得你想要的结果,这样 x
值被定义为从 round(x2 / 10)
获得的 因子:
qplot(f1,y,data = d1,geom =boxplot)+
geom_line(data = d2,aes(x = as.numeric(ordered(round(x2 / 10))) ,y = y2))
I try to display a line on top of a boxplot graph with the x made from factor.
This code work well:
x <- c(91,92,93,125,123,140)
y <- c(200,260,220,300,350,360)
d1 <- data.frame(x=x,y=y)
d1$f1 = factor(round(d1$x/10))
qplot(f1,y,data=d1,geom="boxplot")
d2<-data.frame(x2=c(90,140),y2=c(210,320))
qplot(x2,y2,data=d2,geom="line")
But when i try to add the line to the graph...
qplot(f1,y,data=d1,geom="boxplot") + geom_line(data = d2, aes(x = x2, y=y2))
To see my results: http://jeb-files.s3.amazonaws.com/Clipboard01.jpg
How do I manage to have my line align with my boxplot?
Thanks!
解决方案 A boxplot
requires the x-values to be factors, whereas a geom_line
requires the x-values to be numeric. You can get what you want by modifying the geom_line
call so that the x
value is defined as the numeric version of the ordered factor obtained from round(x2/10)
:
qplot( f1,y,data=d1,geom="boxplot") +
geom_line(data = d2, aes(x = as.numeric(ordered(round(x2/10))), y=y2))
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