按ggplot2中各列的组合来划分图 [英] Faceting plots by combinations of columns in ggplot2
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问题描述
我正在做相关性的组合,并且想在ggplot2中绘制每个组合。然而,我希望每个组合都在一个单独的面板上,而不是一个面板上的所有点。
#制作栏目,在我的我正在做每列之间的相关性(即,col1_col2,col1_col3,col2_col3)
pre>
col1 <-c(1:10)
col2 <-c(12 :3)
col3 <-c(10,12,18,19,20,30,31,32,40,41)
df< - data.frame(col1 ,col2,col3)
g < - ggplot(data = df,aes(x = col1,y = col3))+ geom_point()
我知道这不会让我想要的情节,但我真的难以接受如何在ggplot2中做到这一点。为了清楚起见,我想总共创建三个散点图。
任何帮助都是值得赞赏的!
解决方案
$您的数据
col1 < - c(1:10)
col2 < - c(12:3)$ b $ (10,12,18,19,20,30,31,32,40,41)
#创建data.frame
df< -
rbind(data.frame(x = col1,y = col2,cor =1-2),
data.frame(x = col1,y = col3,cor =1-3) ,
data.frame(x = col2,y = col3,cor =2-3))
#绘制
ggplot(df,aes(x,y) )+ geom_point()+ facet_wrap(〜cor,scales =free)
I am doing combinations of correlations, and would like to plot in ggplot2 each combination. However I want each combination on a separate panel, rather than all the points on one panel.
#making up columns, in my real data I'm doing correlations between each column (ie. col1~col2, col1~col3, col2~col3) col1 <- c(1:10) col2 <- c(12:3) col3 <- c(10, 12, 18, 19, 20, 30, 31, 32, 40, 41) df <- data.frame(col1, col2, col3) g <- ggplot(data=df, aes(x=col1, y=col3)) + geom_point()
I knew this wouldn't make my desired plot, but I'm really stumped as to how to approach this in ggplot2. Just to be clear, I want to make three scatter plots in total.
Any help is appreciated!
解决方案require(ggplot2) # Your data col1 <- c(1:10) col2 <- c(12:3) col3 <- c(10, 12, 18, 19, 20, 30, 31, 32, 40, 41) # Creation of data.frame df <- rbind(data.frame(x=col1, y=col2, cor="1-2"), data.frame(x=col1, y=col3, cor="1-3"), data.frame(x=col2, y=col3, cor="2-3")) # Plotting ggplot(df, aes(x, y)) + geom_point() + facet_wrap(~cor, scales="free")
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