为什么git使用--follow和--reverse记录只返回最后一次提交？ [英] Why does git log with --follow and --reverse return only last commit?

问题描述

我想从一开始就查看文件的所有提交，反转
我跑了

  git log --reverse [file] 
  

它按预期工作。
，但是对于一个重命名的文件，它只显示从它重命名的提交中显示，所以我添加了 - 关注它。

  git log --reverse --follow [file] 
  

但它现在只显示最后一个这是为该文件完成的。

我怎样才能将两者结合起来以获得所需的结果。

解决方案

这似乎是 git中的已知错误。我能看到的唯一工作就是如果你知道文件之前被命名了什么，将它与当前文件一起传递给命令，即

  git log --reverse --follow  -  oldfilename currentfilename 
  

编辑：

以下将做你想做的：

  git log --name-only --pretty =format： --follow< filename> | sort -u | xargs git log --reverse  -  
  

I wanted to view all the commits of a file from the beginning in reverse I ran

git log --reverse [file]

And it worked as expected. but for a renamed file it shows only from the commit in which it was renamed so I added --follow in it.

git log --reverse --follow [file]

but it now shows only the last commit which was done for that file.

How can I combine both to get the desired result.

解决方案

This seems to be known bug in git. The only work around I can see is if you know what the file was named before, pass it along with the current file to the command, i.e.

 git log --reverse --follow -- oldfilename currentfilename

Edit: the following will do what you want:

git log --name-only --pretty="format:"  --follow <filename> | sort -u | xargs git log --reverse --

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