获取404试图从Jersey 2渲染JSP [英] Getting 404 trying to render a JSP from Jersey 2

问题描述

我正在尝试使用Jersey 2和JSP创建一个Web应用程序的简单示例，并将其部署到Glassfish 4.但是，我一直在尝试访问我的唯一资源时遇到404错误。

首先，项目结构：

以下是重要的类和文件：

web.xml 我将Jersey设置为筛选器，而不是servlet，因为我阅读它需要以这种方式进行定义，以便使其能够与JSP一起工作。

 < web-app version =3.0xmlns =http://java.sun.com/xml/ns/javaee
 xmlns：xsi =http：// www .w3.org / 2001 / XMLSchema-instance
 xsi：schemaLocation =
 http://java.sun.com/xml/ns/javaee 
 http：//java.sun的.com / XML / NS / JavaEE的/网络app_3_0.xsd> 
 
< display-name>原型创建的Web应用程序< / display-name> 
 
< filter> 
< filter-name>球衣< / filter-name> 
< filter-class> org.glassfish.jersey.servlet.ServletContainer< / filter-class> 
< init-param> 
< param-name> jersey.config.server.provider.packages< / param-name> 
< param-value> com.xxx.sample-jersey2< / param-value> 
< / init-param> 
< init-param> 
< param-name> jersey.config.servlet.filter.forwardOn404< / param-name> 
< param-value> true< /参数值> 
< / init-param> 
< / filter> 
 
< filter-mapping> 
< filter-name>球衣< / filter-name> 
< url-pattern> / *< / url-pattern> 
< / filter-mapping> 
 
<！ - < welcome-file-list>  - > 
<！ - < welcome-file> index.html< / welcome-file>  - > 
<！ - < welcome-file> index.htm< / welcome-file>  - > 
<！ - < welcome-file> movies.jsp< / welcome-file>  - > 
<！ - < / welcome-file-list>  - > 
 
< / web-app> 
  

movies.jsp 非常简单：

 < html> 
< body> 
< h2>清单影片< / h2> 
< / body> 
< / html> 
  

自定义的ResourceConfig（我甚至不确定需要）

  package com.xxx.jersey2.config; 
 
导入org.glassfish.jersey.filter.LoggingFilter; 
 import org.glassfish.jersey.server.ResourceConfig; 
 import org.glassfish.jersey.server.mvc.jsp.JspMvcFeature; 
 
 public class CustomResourceConfig extends ResourceConfig {
 public CustomResourceConfig（）{
 packages（com.xxx）; 
寄存器（LoggingFilter.class）; 
寄存器（JspMvcFeature.class）; 
 //它也可能是jersey.config.server.mvc.templateBasePath 
属性（jersey.config.server.mvc.templateBasePath，/ WEB-INF / jsp）; 
 // ...根据需要添加更多属性... 
} 
} 
  

和我的电影控制器：

  package com.xxx.jersey2.web; 
 
 import com.xxx.jersey2.model.Movie; 
 import java.util.ArrayList; 
 import java.util.List; 
 import javax.ws.rs.GET; 
 import javax.ws.rs.Path; 
 import org.glassfish.jersey.server.mvc.Viewable; 
 
 @Path（movies）
 public class MoviesController {
 @GET 
 @Path（/ list）
 public Viewable getMovies（） {
列表< Movie> movies = new ArrayList< Movie>（）; 
 
 movies.add（新电影（百万美元宝贝，希拉里斯旺克））; 
 movies.add（新电影（玩具总动员，Buzz Light Year））; 
 movies.add（新电影（饥饿游戏，珍妮弗劳伦斯））; 
 
返回新的可见（movies.jsp）; 
 
 
 
 
 $ b如果我尝试访问 https：// localhost：8181 / sample-jersey2 / 呈现简单的 index.jsp （仅显示Hello World消息）。但是，试图访问 https：// localhost：8181 / sample-jersey2 / movies / list / 会给我一个404错误。
 
 
 
有关此任何想法将不胜感激。 
最好的祝愿
解决方案
您的方向正确。请在web.xml中注册您的自定义资源配置。
 < init-param> 
< param-name> javax.ws.rs.Application< / param-name> 
< param-value> com.xxx.jersey2.config.CustomResourceConfig< / param-value> 
< / init-param> 
  
你可以像你已经做的那样去除init参数jersey.config.server.provider.packages在你的资源配置。最后一件事将返回新的Viewable（movies.jsp）更改为新的Viewable（/ movies.jsp）。希望它能起作用。
 
I'm trying to make a simple example of a web application using Jersey 2 and JSP, and to deploy it on Glassfish 4. However, I keep getting 404 errors trying to access my only resource. 

First, the project structure:



Here are the important classes and files:

web.xml I'm setting Jersey as a filter, instead of a servlet, because I read it needs to be defined that way in order to make it work with JSP.
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="
        http://java.sun.com/xml/ns/javaee
        http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">

  <display-name>Archetype Created Web Application</display-name>

  <filter>
    <filter-name>jersey</filter-name>
    <filter-class>org.glassfish.jersey.servlet.ServletContainer</filter-class>
    <init-param>
      <param-name>jersey.config.server.provider.packages</param-name>
      <param-value>com.xxx.sample-jersey2</param-value>
    </init-param>
    <init-param>
      <param-name>jersey.config.servlet.filter.forwardOn404</param-name>
      <param-value>true</param-value>
    </init-param>
  </filter>

  <filter-mapping>
    <filter-name>jersey</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>

  <!--<welcome-file-list>-->
    <!--<welcome-file>index.html</welcome-file>-->
    <!--<welcome-file>index.htm</welcome-file>-->
    <!--<welcome-file>movies.jsp</welcome-file>-->
  <!--</welcome-file-list>-->

</web-app>
movies.jsp is extremely simple:
<html>
<body>
  <h2>Listing Movies</h2>
</body>
</html>
The custom ResourceConfig (which I'm not even sure I need)
package com.xxx.jersey2.config;

import org.glassfish.jersey.filter.LoggingFilter;
import org.glassfish.jersey.server.ResourceConfig;
import org.glassfish.jersey.server.mvc.jsp.JspMvcFeature;

public class CustomResourceConfig extends ResourceConfig {
    public CustomResourceConfig() {
        packages("com.xxx");
        register(LoggingFilter.class);
        register(JspMvcFeature.class);
        // it may be also jersey.config.server.mvc.templateBasePath
        property("jersey.config.server.mvc.templateBasePath", "/WEB-INF/jsp");
        // ... more properties as needed ...
    }
}
And my controller for the Movies:
package com.xxx.jersey2.web;

import com.xxx.jersey2.model.Movie;
import java.util.ArrayList;
import java.util.List;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import org.glassfish.jersey.server.mvc.Viewable;

@Path("movies")
public class MoviesController {
    @GET
    @Path("/list")
    public Viewable getMovies() {
        List<Movie> movies = new ArrayList<Movie>();

        movies.add(new Movie("Million Dollar Baby", "Hillary Swank"));
        movies.add(new Movie("Toy Story", "Buzz Light Year"));
        movies.add(new Movie("Hunger Games", "Jennifer Lawrence"));

        return new Viewable("movies.jsp");
    }
}
If I try to access https://localhost:8181/sample-jersey2/ the simple index.jsp is rendered (which only shows a Hello World message). However, trying to access https://localhost:8181/sample-jersey2/movies/list/ gives me a 404 error.

Any ideas on this would be greatly appreciated.
Best regards
解决方案
You're in right direction. Please register your custom resource config in web.xml.
     <init-param>
        <param-name>javax.ws.rs.Application</param-name>
        <param-value>com.xxx.jersey2.config.CustomResourceConfig</param-value>
    </init-param>
You can remove the init param jersey.config.server.provider.packages as you're already doing that in your resource config. One last thing change the return new Viewable("movies.jsp") to  new Viewable("/movies.jsp"). Hopefully it will work.

                        
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