将字符串转换为时间并在golang中解析 [英] convert string to time and parse in golang

问题描述

我从文件中读取时间戳，并将值赋给 t ：

t：=2016-11-02 19:23:05 .503705739 +0000 UTC

当我尝试解析字符串：

time，err：= time.Parse（2016-11-02 19:18:57.149197306 +0000 UTC，t ）

结果是：
$ b $ p <0001> 01-01 00:00:00 +0000 UTC

但我预期的结果是：

2016-11-02 19:18：57.149197306 +0000 UTC？

请 解析。你应该使用 Mon Jan 2 15:04:05 MST 2006 （这是魔法值，你可以用你想要的格式创建一个字符串，但是这个日期）在给定的格式，所以在你的情况下，它会是 2006-01-02 15:04:05.000000000 +0000 UTC 加上我不知道的偏移量我的头顶MST。

I'm reading a timestamp from a file, and I assign the value to t:

t := "2016-11-02 19:23:05.503705739 +0000 UTC"

When I attempt to parse the string:

time, err := time.Parse("2016-11-02 19:18:57.149197306 +0000 UTC", t)

The result is:

0001-01-01 00:00:00 +0000 UTC

But I expected result to be:

"2016-11-02 19:18:57.149197306 +0000 UTC" ?

Please advise.

解决方案

You're not correctly providing the layout argument to Parse. You're supposed to be using Mon Jan 2 15:04:05 MST 2006 (this is magic value, you put create a string in the format you want but with that date) in the given format so in your case, it would be 2006-01-02 15:04:05.000000000 +0000 UTC plus the offset which I don't know off the top of my head for MST.

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