“方法需要指示器接收器”在Go编程语言中 [英] "method requires pointer receiver" in Go Programming Language
问题描述
我刚刚看到Go编程语言的演示文稿,并认为我会尝试写几行。一切工作正常,直到我试图在这种情况下使用接口。如何解决这个问题?
I just saw a presentation of the Go programming language and thought I'd try to write a few lines. Everything worked fine until I tried to use an interface in this situation. How do I solve this?
package main
import "fmt"
type entity float32
func (e *entity) inc() {
*e++
}
type incer interface {
inc()
}
func doSomething(i incer) {
i.inc()
}
func main() {
fmt.Println("Hello, 世界")
var e entity = 3
e.inc()
doSomething(e)
fmt.Println(e)
}
我得到编译器错误:
prog.go:24: cannot use e (type entity) as type incer in function argument:
entity does not implement incer (inc method requires pointer receiver)
我想使用一个指针,以便inc()会影响外部的enity功能。什么是我应该使用的语法?
I want to use a pointer so that the inc() will affect the enity outside the function. What is the syntax I should use?
/ Ricky
推荐答案
我认为这里有一些困惑。 inc
是类型 *实体
类型的方法,而不是类型 entity code>(虽然你可以直接在指针上调用值的方法,但你通常不能直接在指针上调用方法)。您可能会困惑的是为什么您可以调用
e.inc()
,而不必执行(& e).inc()
。这是一个鲜为人知的特例,记录在语言的通话部分底部说明如果 x
是可寻址的,并且& x
的方法集包含 m
,那么 xm()
是(& x).m()
。这适用于这种情况,因为 e
是一个变量,所以它是可寻址的;但其他表达式可能不可寻址。但是,我建议您不要使用这个快捷方式,因为这会造成混淆;它让你认为 e
符合接口 inter
,而不是。
I think there is some confusion here. inc
is a method of the type *entity
, and not of the type entity
(while you can call methods on values directly on pointers; you cannot generally call methods on pointers directly on values). What you may be confused about is why you could call e.inc()
, instead of having to do (&e).inc()
. This is a little-known special case documented at the bottom of the Calls section in the language specification, that says if x
is addressable, and &x
's method set contains m
, then x.m()
is shorthand for (&x).m()
. This applies to this case because e
is a variable, so it is addressable; but other expressions may not be addressable. I would recommend that you not use this shortcut, however, as it causes confusion; it makes you think that e
conforms to the interface inter
, while it does not.
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