正确地将参数传递给Go Exec [英] Properly pass arguments to Go Exec

问题描述

我正在努力学习，首先我想尝试把超级简单的网络服务器放在一起来控制我的iTunes。我过去曾多次使用 osascript -e'告诉应用程序iTunes以playpause'多次，并认为我可以在这里简单地将呼叫拒绝给osascript。

I'm trying to learn go and as a start I wanted to try to throw together a super simple web server for controlling my iTunes. I've used osascript -e 'Tell Application "iTunes" to playpause' to this purpose many times in the past and thought I could simply sluff the call off to osascript here.

注释掉say 5命令确实有效。

The commented out "say 5" command does work.

package main

import "exec"
//import "os"

func main() {

    var command = "Tell Application 'iTunes' to playpause"
    //var command = "say 5"

    c := exec.Command("/usr/bin/osascript", "-e", command)
//  c.Stdin = os.Stdin
    _, err := c.CombinedOutput()
    println(err.String());


}

我收到的回应是如下所示 -

The response I am receiving from this is as follows -

jessed@JesseDonat-MBP ~/Desktop/goproj » ./8.out
exit status 1
[55/1536]0x1087f000

我不确定该从哪里出发和任何方向将不胜感激。

I'm not exactly sure where to go from here and any direction would be greatly appreciated.

推荐答案

我得到它与此工作

package main

import (
    "fmt"
    "exec"
)

func main() {
    command := "Tell Application \"iTunes\" to playpause"

    c := exec.Command("/usr/bin/osascript", "-e", command)
    if err := c.Run(); err != nil {
        fmt.Println(err.String())
    }
}

我认为exec.Command（...）会在参数中添加双引号，因此您只需在需要它们的地方转义\。

I think exec.Command(...) adds double quotes to the parameters if there is spaces in them, so you only need to escape \" where you need them.

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