如何获取图像并保存到blobstore？ [英] How to fetch image and save to blobstore?

问题描述

我想从其他网站获取图片（〜250Kb）并将其保存到 Blob存储。由于配额（5Gb免费）vs数据存储（1Gb免费），我想使用Blobstore。我该怎么做？

GAE文档说我应该创建上传表单来使用blobstore，而我并不需要它。

解决方案

我认为这段代码会起作用：

  from __future__ import with_statement＃first line of your代码
 .... 
 from google.appengine.api import urlfetch 
 import mimetypes $ b $ from google.appengine.api导入文件
 ..... 
 image_name ='your_image.png'
 response = urlfetch.fetch（'http：//....../'+ image_name）＃response.status_code == 200 
（mimetype，_ ）= mimetypes.guess_type（image_name）
 file_name = files.blobstore.create（mime_type = mimetype，_blobinfo_uploaded_filename = image_name））
 with files.open（file_name，'a'）as f：
 f.write（response.content）
 files.finalize（file_name）
 blob_key = files.blobstore.get_blob_key（file_name）
  

I would like to fetch images (~250Kb) from another site and save them to blobstore. I would like to use Blobstore due to its quota (5Gb free) vs datastore (1Gb free). How can I do it?

GAE docs say that I should create upload form to use blobstore, which I don't need.

解决方案

I think this code will work:

from __future__ import with_statement                     # first line of your code     
....
from google.appengine.api import urlfetch
import mimetypes
from google.appengine.api import files
.....
image_name = 'your_image.png'
response = urlfetch.fetch('http://....../' + image_name)  # response.status_code == 200 
(mimetype, _) = mimetypes.guess_type(image_name) 
file_name = files.blobstore.create(mime_type= mimetype, _blobinfo_uploaded_filename= image_name))
with files.open(file_name, 'a') as f:                                           
    f.write(response.content)
files.finalize(file_name)                       
blob_key = files.blobstore.get_blob_key(file_name)                                 

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