如何计算距离另一个特定距离的点的纬度？ [英] How to calculate the latlng of a point a certain distance away from another?
问题描述
下面是一张图表：
在地图上画一个圆圈我有一个以米为单位的中心GLatLng（A）和一个半径（r）。 b
$ b
-----------
- / \--
- / \-
/ \
/ \
/ r \
| * ------------- *
\\ A / B
\ /
\ /
-\ / -
- \ - -
-----------
如何计算位置B的GLatLng？假设r与赤道平行。
使用GLatLng.distanceFrom（）方法获得A和B的半径是微不足道的 - 但是以另一种方式周围并非如此。似乎我需要做更重的数学运算。
我们需要一种方法，在给定方位时返回目标点，从源点行进的距离。幸运的是，Chris Veness在的评论时，会发生以下情况圆形环绕着其中一个圆柱。
在北极附近绘制 pointA ，半径为1,000km ：
var pointA = new google.maps.LatLng（85，0）; //接近北极
var radius = 1000; // 1000km
pointA.destinationPoint（90，radius） code>：
To draw a circle on map I have a center GLatLng (A) and a radius (r) in meters.
Here's a diagram:
-----------
--/ \--
-/ \-
/ \
/ \
/ r \
| *-------------*
\ A / B
\ /
\ /
-\ /-
--\ /--
-----------
How to calculate the GLatLng at position B? Assuming that r is parallel to the equator.
Getting the radius when A and B is given is trivial using the GLatLng.distanceFrom() method - but doing it the other way around not so. Seems that I need to do some heavier math.
We will need a method that returns the destination point when given a bearing and the distance travelled from a source point. Luckily, there is a very good JavaScript implementation by Chris Veness at Calculate distance, bearing and more between Latitude/Longitude points.
The following has been adapted to work with the google.maps.LatLng class:
Number.prototype.toRad = function() {
return this * Math.PI / 180;
}
Number.prototype.toDeg = function() {
return this * 180 / Math.PI;
}
google.maps.LatLng.prototype.destinationPoint = function(brng, dist) {
dist = dist / 6371;
brng = brng.toRad();
var lat1 = this.lat().toRad(), lon1 = this.lng().toRad();
var lat2 = Math.asin(Math.sin(lat1) * Math.cos(dist) +
Math.cos(lat1) * Math.sin(dist) * Math.cos(brng));
var lon2 = lon1 + Math.atan2(Math.sin(brng) * Math.sin(dist) *
Math.cos(lat1),
Math.cos(dist) - Math.sin(lat1) *
Math.sin(lat2));
if (isNaN(lat2) || isNaN(lon2)) return null;
return new google.maps.LatLng(lat2.toDeg(), lon2.toDeg());
}
You would simply use it as follows:
var pointA = new google.maps.LatLng(25.48, -71.26);
var radiusInKm = 10;
var pointB = pointA.destinationPoint(90, radiusInKm);
Here is a complete example using Google Maps API v3:
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<title>Google Maps Geometry</title>
<script src="http://maps.google.com/maps/api/js?sensor=false"
type="text/javascript"></script>
</head>
<body>
<div id="map" style="width: 400px; height: 300px"></div>
<script type="text/javascript">
Number.prototype.toRad = function() {
return this * Math.PI / 180;
}
Number.prototype.toDeg = function() {
return this * 180 / Math.PI;
}
google.maps.LatLng.prototype.destinationPoint = function(brng, dist) {
dist = dist / 6371;
brng = brng.toRad();
var lat1 = this.lat().toRad(), lon1 = this.lng().toRad();
var lat2 = Math.asin(Math.sin(lat1) * Math.cos(dist) +
Math.cos(lat1) * Math.sin(dist) * Math.cos(brng));
var lon2 = lon1 + Math.atan2(Math.sin(brng) * Math.sin(dist) *
Math.cos(lat1),
Math.cos(dist) - Math.sin(lat1) *
Math.sin(lat2));
if (isNaN(lat2) || isNaN(lon2)) return null;
return new google.maps.LatLng(lat2.toDeg(), lon2.toDeg());
}
var pointA = new google.maps.LatLng(40.70, -74.00); // Circle center
var radius = 10; // 10km
var mapOpt = {
mapTypeId: google.maps.MapTypeId.TERRAIN,
center: pointA,
zoom: 10
};
var map = new google.maps.Map(document.getElementById("map"), mapOpt);
// Draw the circle
new google.maps.Circle({
center: pointA,
radius: radius * 1000, // Convert to meters
fillColor: '#FF0000',
fillOpacity: 0.2,
map: map
});
// Show marker at circle center
new google.maps.Marker({
position: pointA,
map: map
});
// Show marker at destination point
new google.maps.Marker({
position: pointA.destinationPoint(90, radius),
map: map
});
</script>
</body>
</html>
Screenshot:
UPDATE:
In reply to Paul's comment below, this is what happens when the circle wraps around one of the poles.
Plotting pointA near the north pole, with a radius of 1,000km:
var pointA = new google.maps.LatLng(85, 0); // Close to north pole
var radius = 1000; // 1000km
Screenshot for pointA.destinationPoint(90, radius):
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