如何读取属性文件并使用项目Gradle脚本中的值？ [英] How to read a properties files and use the values in project Gradle script?

问题描述

我正在研究一个Gradle脚本，我需要阅读 local.properties 文件并使用 build中的属性文件中的值。 gradle这个。我正在以下面的方式做。我运行了下面的脚本，它现在抛出一个错误，但它也没有做任何事情，比如创建，删除和复制文件。我试图打印变量的值，并显示正确的值。

有人可以告诉我这是否正确吗？我想另一种方法是定义 gradle.properties 中的所有内容，并在 build.gradle 中使用它。有人可以告诉我如何从 build.properties ？

访问 build.gradle 中的属性。
$ b build.gradle file：

  apply plugin：'java'
 
 //  - 设置发布组
 group ='com.true.test'
 
 / ** 
 *初始化GAVC设置
 * / 
 def buildProperties = new Properties（）
 file（version.properties）。withInputStream {
 stream  - > buildProperties.load（流）
} 
 //如果jenkins构建，将jenkins构建版本添加到版本中。否则，添加快照版本的版本。 
 def env = System.getenv（）
 if（env [BUILD_NUMBER]）buildProperties.test + =。$ {env [BUILD_NUMBER]}
 version = buildProperties.test 
 println$ {version}
 
 // name设置在settings.gradle文件中
 group =com.true.test
 version = buildProperties .test 
 printlnBuilding $ {project.group}：$ {project.name}：$ {project.version}
 
 Properties properties = new Properties（）
 properties .load（project.file（'build.properties'）。newDataInputStream（））
 def folderDir = properties.getProperty（'build.dir'）
 def configDir = properties.getProperty（'config.dir '）
 def baseDir = properties.getProperty（'base.dir'）
 def logDir = properties.getProperty（'log.dir'）
 def deployDir = properties.getProperty（'deploy。 dir'）
 def testsDir = properties.getProperty（'tests.dir'）
 def packageDir = properties.getProperty（'package.dir'）
 def wrapperDir = properties.getProperty（'wrapper .dir'）
 
 
 sourceCompatibility = 1.7 
 compileJava.options.encoding ='UTF-8'
 
知识库{
 maven {urlhttp：//arti.oven.c ：9000 / release} 
} 
 
任务刷卡（类型：删除）{
 println删除$ projectDir / $ {folderDir}
 delete$ projectDir / $ folderDir
删除$ projectDir / $ logDir
删除$ projectDir / $ deployDir
删除$ projectDir / $ packageDir
删除$ projectDir / $ testsDir
 mkdir（$ projectDir / $ {folderDir}）
 mkdir（projectDir / $ {logDir}）
 mkdir（projectDir / $ {deployDir}）
 mkdir（projectDir / $ {packageDir}）
 mkdir（projectDir / $ {testsDir}）
} 
任务prepConfigs（类型：Copy，覆盖：true，dependsOn： （'$ {projectDir} / $ {folderDir}'中的
）{
 println$ {projectDir} / $ {folderDir}和$ {projectDir} / $ {configDir}的名称
） 
转换为（'$ {projectDir} / $ configDir}'）
i nclude（'*。xml'）
} 
  

build。属性 file：

 ＃--------------- -------------------------------------------------- 
＃常规设置
＃-------------------------------------- --------------------------- 
 application.name = Admin 
 project.name = Hello Cool 
 
＃--------------------------------------------- -------------------- 
＃ant建立目录
＃----------------- ------------------------------------------------ 
 sandbox.dir = $ {projectDir} /../ .. 
 reno.root.dir = $ {sandbox.dir} / Reno 
 ant.dir = $ {projectDir} / ant 
 build.dir = $ {ant.dir} / build 
 log.dir = $ {ant.dir} / logs 
 config.dir = $ {ant.dir} / configs 
 deploy.dir = $ {ant.dir} / deploy 
 static.dir = $ {ant.dir} / static 
 package.dir = $ {ant.dir} / package 
 tests。 dir = $ {ant.dir} / tests 
 tests.logs.dir = $ {tests.dir} / logs 
 external.dir = $ {sandbox.dir} / FlexCommon / External 
外部.lib.dir = $ {external.dir} / libs 
  

解决方案

如果使用默认的 gradle.properties 文件，则可以直接从 build.gradle 文件中访问属性：

gradle.properties ：

  applicationName = Admin 
 projectName = Hello Cool 
  

build.gradle ：

 任务printProps {
 doFirst {
 println applicationName 
 println projectName 
 
 
 code 
 
 
 
如果你需要访问一个自定义文件，或访问其中包含。的属性（因为看起来您需要这样做），您可以在 build.gradle  file：
  def props = new Properties（）
 file build.properties）。withInputStream {props.load（it）} 
 
任务printProps {
 doFirst {
 printl n props.getProperty（application.name）
 println props.getProperty（project.name）
} 
} 
  
查看本节Gradle文档获取更多信息。
 
 
 
编辑
 
 
 
 d喜欢动态设置这些属性中的一部分（如下面的注释中所提到的），您可以创建一个 properties.gradle 文件（名称不重要）并且需要它在 build.gradle 脚本中。
 
 
 
  properties.gradle  
 
 
  ext {
 subPath =some / sub / directory
 fullPath =$ projectDir / $ subPath

  
  build.gradle  
  apply from：'properties.gradle'
 
 //打印完整扩展路径
 println fu llPath 
  
 
I am working on a Gradle script where I need to read the local.properties file and use the values in the properties file in build.gradle. I am doing it in the below manner. I ran the below script and it is now throwing an error, but it is also not doing anything like creating, deleting, and copying the file. I tried to print the value of the variable and it is showing the correct value.


Can someone let me know if this is correct way to do this? I think the other way is to define everything in the gradle.properties and use it in the build.gradle. Can someone let me know how could I access the properties in build.gradle from build.properties?

build.gradle file:
apply plugin: 'java'

//-- set the group for publishing
group = 'com.true.test'

/**
 * Initializing GAVC settings
 */
def buildProperties = new Properties()
file("version.properties").withInputStream {
        stream -> buildProperties.load(stream)
}
//if jenkins build, add the jenkins build version to the version. Else add snapshot version to the version.
def env = System.getenv()
if (env["BUILD_NUMBER"]) buildProperties.test+= ".${env["BUILD_NUMBER"]}"
version = buildProperties.test
println "${version}"

//name is set in the settings.gradle file
group = "com.true.test"
version = buildProperties.test
println "Building ${project.group}:${project.name}:${project.version}"

Properties properties = new Properties()
properties.load(project.file('build.properties').newDataInputStream())
def folderDir = properties.getProperty('build.dir')
def configDir = properties.getProperty('config.dir')
def baseDir  = properties.getProperty('base.dir')
def logDir  = properties.getProperty('log.dir')
def deployDir  = properties.getProperty('deploy.dir')
def testsDir  = properties.getProperty('tests.dir')
def packageDir  = properties.getProperty('package.dir')
def wrapperDir  = properties.getProperty('wrapper.dir')


sourceCompatibility = 1.7
compileJava.options.encoding = 'UTF-8'

repositories {
     maven { url "http://arti.oven.c:9000/release" }
  }

task swipe(type: Delete) {
         println "Delete $projectDir/${folderDir}"
         delete "$projectDir/$folderDir"
         delete "$projectDir/$logDir"
         delete "$projectDir/$deployDir"
         delete "$projectDir/$packageDir"
         delete "$projectDir/$testsDir"
         mkdir("$projectDir/${folderDir}")
         mkdir("projectDir/${logDir}")
         mkdir("projectDir/${deployDir}")
         mkdir("projectDir/${packageDir}")
         mkdir("projectDir/${testsDir}")
}
task prepConfigs(type: Copy, overwrite:true, dependsOn: swipe) {
    println "The name of ${projectDir}/${folderDir} and ${projectDir}/${configDir}"
    from('${projectDir}/${folderDir}')
    into('${projectDir}/$configDir}')
    include('*.xml')
}
build.properties file:
# -----------------------------------------------------------------
# General Settings
# -----------------------------------------------------------------
application.name  = Admin
project.name = Hello Cool

# -----------------------------------------------------------------
# ant build directories
# -----------------------------------------------------------------
sandbox.dir = ${projectDir}/../..
reno.root.dir=${sandbox.dir}/Reno
ant.dir = ${projectDir}/ant
build.dir = ${ant.dir}/build
log.dir  = ${ant.dir}/logs
config.dir = ${ant.dir}/configs
deploy.dir  = ${ant.dir}/deploy
static.dir =  ${ant.dir}/static
package.dir = ${ant.dir}/package
tests.dir = ${ant.dir}/tests
tests.logs.dir = ${tests.dir}/logs
external.dir = ${sandbox.dir}/FlexCommon/External
external.lib.dir = ${external.dir}/libs

解决方案
If using the default gradle.properties file, you can access the properties directly from within your build.gradle file:

gradle.properties:
applicationName=Admin
projectName=Hello Cool
build.gradle:
task printProps {
    doFirst {
        println applicationName
        println projectName
    }
}
If you need to access a custom file, or access properties which include . in them (as it appears you need to do), you can do the following in your build.gradle file:
def props = new Properties()
file("build.properties").withInputStream { props.load(it) }

task printProps {
    doFirst {
        println props.getProperty("application.name")
        println props.getProperty("project.name")
    }
}
Take a look at this section of the Gradle documentation for more information.

Edit

If you'd like to dynamically set up some of these properties (as mentioned in a comment below), you can create a properties.gradle file (the name isn't important) and require it in your build.gradle script.

properties.gradle:
ext {
    subPath = "some/sub/directory"
    fullPath = "$projectDir/$subPath"
}
build.gradle
apply from: 'properties.gradle'

// prints the full expanded path
println fullPath


                        
这篇关于如何读取属性文件并使用项目Gradle脚本中的值？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！