从控制器中捕获的异常抛出异常 [英] Exception Thrown From Service Not Being Caught in Controller

问题描述

在我的Grails服务中，我有如下代码：

  def createCharge（chargeParams）{
 try { 
 def charge = Charge.create（chargeParams）
} catch（CardException e）{
 throw e 
} 
} 
  

在我的控制器中，我执行以下操作：

 尝试{
 service.createCharge（chargeParams）
} catch（CardException e）{
 
} 
  

但是，我的控制器没有捕获CardException的重新抛出。如果我通过以下方式将CardException包装在RuntimeException中：

  throw new RuntimeException（e）
  

和/或从catch中删除签名以仅捕获（e）而不键入它，它可以工作，但我从异常中丢失了一些信息，例如消息。

值得注意的是，CardException是一个异常，而不是一个RuntimeException。我不确定这是否重要。

解决方案

与Java不同，您不必声明（checked）由Groovy方法抛出，因为任何未声明的已检查异常都包装在 UndeclaredThrowableException 中。所以这个：

  def createCharge（chargeParams）{
 try {
 def charge = Charge.create（ （CardException e）{
 throw e 
} 
} 
  

实际上与以下内容相同：

  def createCharge（chargeParams）throws UndeclaredThrowableException {
尝试{
 def charge = Charge.create（chargeParams）
} catch（CardException e）{
 throw new UndeclaredThrowableException（e）
} 
} 
  

上述抛出的异常，显然不会被捕获：

  try {
 service.createCharge（chargeParams）
} catch（CardException e）{
 
} 
  

但它会被抓住：

  try {
 service.createCharge（chargeParams）
} catch（e）{
 
} 
  

因为这只是一个简写：

  try {
 service.createCharge（chargeParams）
} catch（Exception e）{
 
} 
  




In my Grails service I have code like the following:

def createCharge(chargeParams) {
  try {
    def charge = Charge.create(chargeParams)
  } catch (CardException e) {
    throw e
  }
}

From my controller I do the following:

try  {
   service.createCharge(chargeParams)
} catch(CardException e) {

}

However, my controller is not catching the re-throwing of the CardException. If I wrap CardException in a RuntimeException via:

throw new RuntimeException(e)

and/or remove the signature from the catch to just catch(e) without typing it, it works, but I lose some information from the exception, like the message.

As a note, CardException is an Exception, not a RuntimeException. I'm not sure if that matters.

解决方案

Unlike Java, you don't have to declare the (checked) exceptions that are thrown by a Groovy method, because any undeclared checked exceptions are wrapped in an UndeclaredThrowableException. So this:

def createCharge(chargeParams) {
  try {
    def charge = Charge.create(chargeParams)
  } catch (CardException e) {
    throw e
  }
}

is effectively the same as:

def createCharge(chargeParams) throws UndeclaredThrowableException {
  try {
    def charge = Charge.create(chargeParams)
  } catch (CardException e) {
    throw new UndeclaredThrowableException(e)
  }
}

the exception thrown by the above, obviously wouldn't be caught by:

try  {
   service.createCharge(chargeParams)
} catch(CardException e) {

}

But it will be caught by:

try  {
   service.createCharge(chargeParams)
} catch(e) {

}

Because this is just a shorthand for:

try  {
   service.createCharge(chargeParams)
} catch(Exception e) {

}

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