我如何摆脱“ - ”使用grep和上下文行时的行分隔符？ [英] How do I get rid of "--" line separator when using grep with context lines?

问题描述

我有一个名为compare.txt的文本文件，我想提取包含模式nmse_gain_constant的每一行后面的单行。以下命令让我关闭：

I have a text file named compare.txt that I want to extract the single line that follows every line that contains the pattern "nmse_gain_constant". The following command gets me close:

grep -A 1 nmse_gain_constant compare.txt | grep -v nmse_gain_constant

但是，这包括每行所需文本之间的分隔符 - 。任何简单的想法如何摆脱 - 线？

But this includes a separator "--" line between every line of desired text. Any easy ideas how to get rid of the "--" lines?

我会给你一些示例文本，但 - 字符被错误地解释作为控制字符，你会看到什么是不正确的。

I'd give you some example text here, but the "--" characters get erroneously interpreted by this web post as control characters and what you would see is not correct.

推荐答案

我这样做：

 grep ... | grep -v -- "^--$"

但是这也适用！

grep --no-group-separator ...

它不会吐出那个 - 或甚至是一个空行。

And it doesn't spit out that "--" or even a blank line.

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