我如何摆脱“--"将 grep 与上下文行一起使用时的行分隔符? [英] How do I get rid of "--" line separator when using grep with context lines?

问题描述

我有一个名为 compare.txt 的文本文件，我想在其中提取包含模式 nmse_gain_constant 的每一行后面的单行.以下命令让我关闭:

I have a text file named compare.txt where I want to extract the single line that follows every line that contains the pattern nmse_gain_constant. The following command gets me close:

grep -A 1 nmse_gain_constant compare.txt | grep -v nmse_gain_constant

但这包括每行所需文本之间的分隔符 -- 行.任何简单的想法如何摆脱 -- 行?

But this includes a separator -- line between every line of desired text. Any easy ideas how to get rid of the -- lines?

示例:对于看起来像的输入文件

Example: for an input file that looks like

line
line
nmse_gain_constant matching line
line after first match
line
line
nmse_gain_constant another matching line
line after second match
line
nmse_gain_constant a third matching line
line after third match

输出是

line after first match
--
line after second match
--
line after third match

但我只想拥有

line after first match
line after second match
line after third match

推荐答案

我这样做:

 grep ... | grep -v -- "^--$"

但这也适用(在许多操作系统上，并非在所有操作系统上)！

But this works too (on many, not all OS'es)!

grep --no-group-separator ...

它不会吐出--"甚至是一个空行.

And it doesn't spit out that "--" or even a blank line.

这篇关于我如何摆脱“--"将 grep 与上下文行一起使用时的行分隔符?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！