如何搜索一个字符串，并将其替换为其他字符串在Linux？ [英] how to search for a string and replace it with other string in linux?

问题描述

我想为字符串进行搜索，并用另一个字符串替换 / code>递归地在一个目录下。
例如：
我想搜索一个字符串

var gaJsHost =（（https：= = document.location.protocol）https：// ssl。：http：// www。）;

和用替换它

var _gaq = _gaq || []; _ gaq.push（['_ setAccount'，'UA-7044592-1']）; _ gaq.push（['_ setDomainName'，'news4u.com']）; _ gaq.push（['_trackPageview']）;

如何实现它？

解决方案

<使用 find 查找所有文件， xargs 运行 sed

  find dir -type f | xargs sed -i.bak的＃从＃到＃'
  

可以找到 dir ，并用替换到，备份扩展名为.bak的原始文件

NB from 是一个基本的正则表达式，所以您需要转义您正在搜索的字符串中的任何BRE元字符。在单个文件上测试sed命令以使其运行是个好主意：

  sed's＃from＃到＃'档案> test.out 
  

这将替换文件，而不是修改 file 它会将输出写入 test.out ，以便检查结果。

I want to search for a string and replace it with another string recursively under a directory. for example: I want to search for a string

"var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www.");"

and replace it with

var _gaq = _gaq || [];_gaq.push(['_setAccount', 'UA-7044592-1']);_gaq.push(['_setDomainName', 'news4u.com']);_gaq.push(['_trackPageview']);

How to achieve it ?

解决方案

Use find to find all files, and xargs to run sed to modify them:

find dir -type f | xargs sed -i.bak 's#from#to#'

that will find all files under dir and replace from with to, backing up the original files with the extension ".bak"

N.B. from is a basic regular expression, so you will need to escape any BRE metacharacters in the string you are searching for. It would be a good idea to test the sed command on a single file to get it working:

sed 's#from#to#' file > test.out

That will do the replacements to file but instead of modifying file it will write the output to test.out so you can check the results.

这篇关于如何搜索一个字符串，并将其替换为其他字符串在Linux？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！