在unix上打印出整数文字 [英] Printing out integer literals occurences on unix
本文介绍了在unix上打印出整数文字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我尝试使用grep命令打印出foo.txt文件中所有出现的整数字面值,但似乎无法找到方法。
我能想到的唯一想法就是使用[0-9]作为我的模式,但是它会打印所有出现数字的行而不仅仅是文字。
编辑:说foo.txt包含:
string string1 =Hello world;
cout <<<<< lt1;<< lt1;< ltl< lt;<
$ b然后,预期的输出将是:
cout<< string1.at(2)<< endl;
cout<< string1at(3)<< endl;
< / code>< / pre>
解决方案有些人喜欢这样:
awk - F[()]'$ 2'foo.txt
cout<< string1.at(2)<< endl;;
cout<<< string1at(3)<< ; endl;
或者确定它包含ns数字:
awk -F[()]'$ 2〜/ [0-9] + /'文件
cout<< string1.at(2)<< ENDL;
cout<< string1at(3)<< ENDL;
I"m trying to use the grep command to print out all occurrences of integer literals in a foo.txt file, but I can't seem to find a way how.
The only think I can think of for this is using [0-9] as my pattern, but that prints all lines with occurrences of the number rather than just the literals.
EDIT: Say foo.txt contains:
string string1 = "Hello world";
cout << string1.at(2) << endl;
cout << string1at(3) << endl;
Then the expected output would be:
cout << string1.at(2) << endl;
cout << string1at(3) << endl;
解决方案 Some like this:
awk -F"[()]" '$2' foo.txt
cout << string1.at(2) << endl;
cout << string1at(3) << endl;
Or to make sure it contains numbers between parentheses:
awk -F"[()]" '$2~/[0-9]+/' file
cout << string1.at(2) << endl;
cout << string1at(3) << endl;
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