在列表上查找全部的Groovy过滤条件 [英] Groovy filter criteria on findAll on a list

问题描述

我试图在列表中使用findAll构建动态过滤器。我有一个变量，只有在不为空时才需要包含在过滤器中。

  @Test 
 void testSample（）{
 def list = [new Employee（age：22， isManager：false），
新员工（年龄：23​​，isManager：true），
新员工（年龄：22，isManager：true）]设为
 
 def var = 22; 
 String query1 =it.age == var& it.isManager == true
 String query2 =it.isManager == true
 
 println list 
 println list.findAll {var？ query1：query2} //应该给1个记录年龄= 22和经理
 var = null; 
 println list.findAll {var？ query1：query2} //应该给2个记录专用管理器
 
} 
  

他们都给出了所有的记录。无论如何，我可以在一种情况下实现这一点，而无需编写多元查询？

看起来像下面这样（但这不起作用）

  println list.findAll {
 if（var）it.age == var&& 
 it.isManager == true 
} 
  

解决方案

  def list = [new Employee（age： 22，isManager：false），
新员工（年龄：23​​，isManager：true），
新员工（年龄：22，isManager：true）]设置
 
 def var = 22; 
 Closure query1 = {it.age == var&& it.isManager == true} 
 Closure query2 = {it.isManager == true} 
 
 println list 
 println list.findAll（var？query1：query2）//应该给1个记录年龄= 22和经理
 var = null; 
 println list.findAll（var？query1：query2）//应该给2个只记录管理器
  

编辑

您的意思是：

  println list。 findAll {（var？it.age == var：true）&& it.isManager == true} 
  

或者更好：

  println list.findAll {（var！= null？it.age == var：true）&& it.isManager == true} 
  

I trying to build dynamic filters using findAll on a list. I have a variable that needs to be included in the filter only if not null.

 @Test
    void testSample(){
        def list = [ new Employee(age:22, isManager:false), 
                     new Employee(age:23, isManager:true), 
                     new Employee(age:22, isManager:true) ] as Set

        def var = 22;
        String query1 = "it.age == var && it.isManager == true "
        String query2 = "it.isManager == true"

        println list
        println list.findAll { var ? query1 : query2 } // Should give 1 record age = 22 and manager
        var = null;
        println list.findAll { var ? query1 : query2 } // should give 2 records-only manager

    }

Both of them giving all the records. Is there anyway I can achieve this in one condition without need to write muiltiple queries ?

Looking some like below (this doesn't work though)

println list.findAll{
                if(var) it.age == var &&
                it.isManager == true
        }

解决方案

Try with Closures rather than Strings describing what you want to do:

def list = [ new Employee(age:22, isManager:false), 
             new Employee(age:23, isManager:true), 
             new Employee(age:22, isManager:true) ] as Set

def var = 22;
Closure query1 = { it.age == var && it.isManager == true }
Closure query2 = { it.isManager == true }

println list
println list.findAll( var ? query1 : query2 ) // Should give 1 record age = 22 and manager
var = null;
println list.findAll( var ? query1 : query2 ) // should give 2 records-only manager

Edit

Do you mean:

println list.findAll{ ( var ? it.age == var : true ) && it.isManager == true }

Or better:

println list.findAll{ ( var != null ? it.age == var : true ) && it.isManager == true }

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