如何舍入到最接近的50或100？ [英] how to round to nearest 50 or 100?

问题描述

我有数字（十进制）我想将它舍入到最接近的50：

1. 122 => round to 150


2. 177 =>轮到200
   
3. 157 =>轮到200
   
4. 57 =>轮到100 ;


5. 37 =>轮到50;
   
6. 1557 =>轮到1600
   
7. 3537 =>轮到3550
   

如何用java / groovy做到这一点？

解决方案

Groovy x + （50 - （x％50？：50））：

  def round50up = {int x - > 
x +（50  - （x％50？：50））
} 
 
 assert round50up（122）== 150 
 assert round50up（177）== 200 
 assert round50up（157）== 200 
 assert round50up（57）== 100 
 assert round50up（37）== 50 
 assert round50up（1557）== 1600 
 assert round50up（3537）== 3550 
 assert round50up（100）== 100 
 assert round50up（200）== 200 
 assert round50up（250）== 250 
  

测试 此处 。

I have numbers (in decimal) I want to round it to "nearest 50":

1. 122 => round to 150
2. 177 => round to 200
3. 157 => round to 200
4. 57 => round to 100;
5. 37 => round to 50;
6. 1557 => round to 1600
7. 3537 => round to 3550

how to do that with java/groovy ?

解决方案

Groovy x + (50 - (x % 50 ?: 50)) :

def round50up = { int x ->
    x + ( 50 - ( x % 50 ?: 50 ) )
}

assert round50up( 122  ) == 150 
assert round50up( 177  ) == 200 
assert round50up( 157  ) == 200 
assert round50up( 57   ) == 100 
assert round50up( 37   ) == 50 
assert round50up( 1557 ) == 1600 
assert round50up( 3537 ) == 3550 
assert round50up( 100  ) == 100 
assert round50up( 200  ) == 200 
assert round50up( 250  ) == 250

Test it here.

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