Python舍入到最接近的0.25 [英] Python round to nearest 0.25

问题描述

我想将整数四舍五入为最接近的0.25个十进制值，如下所示:

I want to round integers to the nearest 0.25 decimal value, like this:

import math

def x_round(x):
    print math.round(x*4)/4

x_round(11.20) ## == 11.25
x_round(11.12) ## == 11.00
x_round(11.37) ## == 11.50

这给我以下Python错误:

This gives me the following error in Python:

Invalid syntax

推荐答案

函数math.round不存在，只需使用内置的round

The function math.rounddoes not exist, just use the built in round

def x_round(x):
    print(round(x*4)/4)

请注意，print是Python 3中的一个函数，因此需要括号.

Note that print is a function in Python 3, so the parentheses are required.

目前，您的函数未返回任何内容.最好从函数中返回值，而不是打印出来.

At the moment, your function doesn't return anything. It might be better to return the value from your function, instead of printing it.

def x_round(x):
    return round(x*4)/4

print(x_round(11.20))

如果要舍入，请使用math.ceil.

def x_round(x):
    return math.ceil(x*4)/4

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