MySQL左连接+最小 [英] MySQL Left Join + Min

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问题描述

看起来很简单的MySQL问题,但我从来没有这样做过。



我有两个表格,项目和价格,很多关系。

 物品表
id,名称

物品表
id,item_id ,价格

其中

  prices.item_id = items.id 

到目前为止: p>

  SELECT items.id,items.name,MIN(prices.price)
FROM items
LEFT JOIN价格ON items.id = prices.item_id
GROUP BY items.id

我怎么也为最低价格返回相应的price.id?感谢!

解决方案

如果以最低价格存在多个价格记录,这将返回Items中记录的多个记录:

  select items.id,items.name,prices.price,prices.id 
from items

items.id = prices.item_id
和prices.price =(
)从价格
中选择min(price)
where item_id = items。 id

);


Seemingly simple MySQL question, but I've never had to do this before..

I have two tables, items and prices, with a one-to-many relationship.

Items Table
id, name

Prices Table
id, item_id, price

Where

prices.item_id = items.id

What I have so far:

SELECT items.id, items.name, MIN(prices.price)
FROM items
LEFT JOIN prices ON items.id = prices.item_id
GROUP BY items.id

How do I also return the corresponding prices.id for that minimum price? Thanks!

解决方案

This will return multiple records for a record in Items if there are multiple Prices records for it with the minimum price:

select items.id, items.name, prices.price, prices.id
from items
left join prices on (
    items.id = prices.item_id 
    and prices.price = (
        select min(price)
        from prices
        where item_id = items.id
    )
);

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