Gulp TypeError:path.join的参数必须是字符串 [英] Gulp TypeError: Arguments to path.join must be strings
问题描述
TypeError :path.join的参数必须是字符串
这是我的gulpfile.js
var gulp = require('gulp');
var jade = require('gulp-jade');
var sass = require('gulp-ruby-sass');
var watch = require('gulp-watch');
gulp.task('sass',function(){
return gulp.src('sass / *。sass')
.pipe(sass())
.pipe(gulp.dest('./ css'));
});
gulp.task('watch',function(){
gulp.watch('./ sass / *。sass',['sass']);
})
我使用了gulp-slash,但它不起作用。
使用语法更改 in gulp-ruby-sass 从1.0.0-alpha开始,您需要使用 gulp-ruby-sass()
来代替 gulp.src()
从文件或目录编译Sass。
如果您尝试使用原始语法与更新或最新版本,您可能会遇到以下错误:
$ b
TypeError:path.join的参数必须是字符串$ c $例如,使用gulp.src()的0.7.x和更早版本中的原始语法,现在已被弃用:
var gulp = require('gulp');
var sass = require('gulp-ruby-sass');
$ b $ // gulp-ruby-sass:0.7.1
gulp.task('sass',function(){
return gulp.src('path / to / scss ')
.pipe(sass({style:'expanded'}))
.pipe(gulp.dest('path / to / css'));
});
使用gulp-ruby-sass()作为吞食源适配器:
$ b
// gulp-ruby-sass:1.x
gulp.task ('sass',function(){
return sass('path / to / scss',{style:'expanded'})
.pipe(gulp.dest('path / to / css' ));
});
请注意return语句第一行的不同。
在使用gulp-ruby-sass 1.0.0-alpha时,请记住,在编写本文时,globs不受支持。
I have i problem with gulp-ruby-sass. When i try to run the watch task and change some .sass files it occurs error:
TypeError: Arguments to path.join must be strings
Here is my gulpfile.js
var gulp = require('gulp');
var jade = require('gulp-jade');
var sass = require('gulp-ruby-sass');
var watch = require('gulp-watch');
gulp.task('sass', function() {
return gulp.src('sass/*.sass')
.pipe(sass())
.pipe(gulp.dest('./css'));
});
gulp.task('watch', function() {
gulp.watch('./sass/*.sass', ['sass']);
})
I used gulp-slash but it don't works.
With the syntax changes in gulp-ruby-sass starting from 1.0.0-alpha, you'll need to use gulp-ruby-sass()
instead of gulp.src()
to compile your Sass from a file or directory.
If you try to use the original syntax with newer or latest versions, you may encounter the following error:
TypeError: Arguments to path.join must be strings
For example, the original syntax in 0.7.x and earlier using gulp.src(), now deprecated:
var gulp = require('gulp');
var sass = require('gulp-ruby-sass');
// gulp-ruby-sass: 0.7.1
gulp.task('sass', function() {
return gulp.src('path/to/scss')
.pipe(sass({ style: 'expanded' }))
.pipe(gulp.dest('path/to/css'));
});
The new syntax introduced in 1.x using gulp-ruby-sass() as a gulp source adapter:
// gulp-ruby-sass: 1.x
gulp.task('sass', function() {
return sass('path/to/scss', { style: 'expanded' })
.pipe(gulp.dest('path/to/css'));
});
Notice the difference in the first line of the return statement.
Also keep in mind, as of this writing when using gulp-ruby-sass 1.0.0-alpha, globs are not supported yet.
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