Gulp-sass不会编译成CSS [英] Gulp-sass will not compile to CSS
问题描述
我无法将grunt-sass编译为.css。看到了一些其他类似的帖子和使用建议的负载,但似乎没有工作。
我可以让其他插件工作正常(例如'删除'删除的东西,显示这里)所以看起来我的环境是好的,我可以得到普通的香草sass编译/监视工作正常。
以下是我的设置以防万一:
OSX Maverics 10.9.5
$ ruby -v
ruby 2.0.0p481(2014-05-08修订版45883)[universal.x86_64-darwin13]
$ sass -v
Sass 3.4.9(Selective Steve)
$ npm -v
2.1.12
$ brew -v
Homebrew 0.9.5
以下是项目目录结构:
├──index.html
│
├──scss
│└──base.scss
│├──_partial1.scss
│└──_partial2.scss
│
├──资产
│└──css
│└──什么都没有!
│
├──测验
│└──save.txt
│
├──gulpfile.js
│
└─ ──node_modules
└──etc ...
这是我的gulpfile.js:
var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');
$ b gulp.task('gsas',function(){
gulp.src('./scss/base.scss')
.pipe(sass({includePaths: ['./scss/']}))
.pipe(gulp.dest('./ assets / css'))
});
$ b del(['!deltest / save.txt','deltest / delete.txt'],函数(err,deletedFiles){
console.log('Files deleted:', deletedFiles.join(','));
});
gulp.task('default',function(){
console.log('AAAAAAAAAAAAAAAARGH!');
});
任何人都可以看到这里有什么问题吗?
< hr>
已更新 - 执行相同的任务时会在Windows窗口中静默失败:
以下是gulpfile .js从窗口框测试,我甚至不@importing任何partials(目录结构正如所示的任务设置,我直接从实际的插件示例中所示): p>
var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');
$ b gulp.task('sass',function(){
gulp.src('./ scss / *。scss')
.pipe(sass())
.pipe(gulp.dest('./ css'));
});
$ b del(['delete / delete.txt','!delete / save.txt'],function(err,deletedFiles){
console.log('Files deleted:', deletedFiles.join(','));
});
$ b $ gulp.task('default',function(){
console.log(Made it!);
});
在这个例子中,我得到'del'任务运行良好但gulp-sass失败如果你想让 sass
任务成为可能,那么这个任务就会变得非常困难。
gulp
时执行,将它添加为默认
任务的依赖项: gulp.task('default',['sass'],function(){
//其他东西
});
I'm not able to get grunt-sass to compile to .css. Have seen a load of other similar posts and utilized suggestions but nothing seems to work.
I can get other plugins working fine (for example 'del' to delete stuff, shown here) so it seems my environment is ok, and i can get ordinary vanilla sass compile/watch to work fine.
Here's my setup just in case:
OSX Maverics 10.9.5
$ ruby -v
ruby 2.0.0p481 (2014-05-08 revision 45883) [universal.x86_64-darwin13]
$ sass -v
Sass 3.4.9 (Selective Steve)
$ npm -v
2.1.12
$ brew -v
Homebrew 0.9.5
Here's the project directory structure:
├── index.html
│
├── scss
│ └── base.scss
│ ├── _partial1.scss
│ └── _partial2.scss
│
├── assets
│ └── css
│ └── Nothing yet!
│
├── deltest
│ └── save.txt
│
├── gulpfile.js
│
└── node_modules
└── etc ...
Here's my gulpfile.js:
var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');
gulp.task('gsas', function() {
gulp.src('./scss/base.scss')
.pipe(sass({ includePaths : ['./scss/'] }))
.pipe(gulp.dest('./assets/css'))
});
del(['!deltest/save.txt', 'deltest/delete.txt'], function (err, deletedFiles) {
console.log('Files deleted:', deletedFiles.join(', '));
});
gulp.task('default', function() {
console.log('AAAAAAAAAAAAAAAARGH!');
});
Can anyone see what is wrong here?
UPDATED - with same task silently failing on a windows box:
Here's the gulpfile.js from the windows box test and I'm not even @importing any partials (the dir structure is exactly as shown in the task setup, which i pulled straight from the actual plugin example):
var gulp = require('gulp');
var sass = require('gulp-sass');
var del = require('del');
gulp.task('sass', function () {
gulp.src('./scss/*.scss')
.pipe(sass())
.pipe(gulp.dest('./css'));
});
del(['delete/delete.txt', '!delete/save.txt'], function (err, deletedFiles) {
console.log('Files deleted:', deletedFiles.join(', '));
});
gulp.task('default', function () {
console.log("Made it!");
});
In this example again I'm getting the 'del' task to run fine but gulp-sass fails silently and it's really baffling.
If you want the sass
task to execute when you run gulp
from the command-line, add it as a dependency of the default
task:
gulp.task('default', ['sass'], function() {
//other stuff
});
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