HTTP POST响应到的WebView在安卓 [英] HTTP POST response into WebView in android
本文介绍了HTTP POST响应到的WebView在安卓的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图使用HTTP连接到页面 帖子。我做一个HTTP POST创建 一个web视图。我需要重定向到从web视图另一个页面。但是,在单击继续按钮时异常。
我的code是
公共类ZHttpPostProjActivity延伸活动{
/ **第一次创建活动时调用。 * /
私人的WebView mWebView;
私人ProgressDialog进度;
私有静态最后字符串变量=ZHttpPostProjActivity;
@覆盖
公共无效的onCreate(包savedInstanceState){
super.onCreate(savedInstanceState);
的setContentView(R.layout.web_view);
mWebView =(web视图)findViewById(R.id.webview);
WebSettings webSettings = mWebView.getSettings();
webSettings.setJavaScriptEnabled(真正的);
webSettings.setDomStorageEnabled(真正的);
进度= ProgressDialog.show(ZHttpPostProjActivity.this,,
载入中...);
POSTDATA();
}
私人最终字符串URL_REGISTER =https://www.paypal.com/checkout;
公共无效POSTDATA(){
BufferedReader中的BufferedReader = NULL;
尝试 {
名单<的NameValuePair> namevaluepairs中=新的ArrayList<的NameValuePair>();
nameValuePairs.add(新BasicNameValuePair(用户名,用户名));
nameValuePairs.add(新BasicNameValuePair(密码,密码));
HttpClient的HttpClient的=新DefaultHttpClient();
HttpPost httppost =新HttpPost(URL_REGISTER);
httppost.setEntity(新UrlEn codedFormEntity(namevaluepairs中,
HTTP.UTF_8));
HTT presponse响应= httpclient.execute(httppost);
的BufferedReader =新的BufferedReader(新的InputStreamReader(响应
。.getEntity()的getContent()));
StringBuffer的StringBuffer的=新的StringBuffer();
串线=;
串LineSeparator = System.getProperty(line.separator);
而((行= bufferedReader.readLine())!= NULL){
的StringBuffer.append(行+ LineSeparator);
}
bufferedReader.close();
字符串WEBDATA = stringBuffer.toString();
Log.i(TAG +网络数据,WEBDATA);
//字符串WEBDATA =新
// BasicResponseHandler()用handleResponse(响应)。
Log.i(TAG,Httppost.getURI()的toString()。
+ httppost.getURI()的toString())。
mWebView.setWebViewClient(新WebViewClient(){
公共布尔shouldOverrideUrlLoading(web视图查看,字符串URL){
Log.i(TAG,处理的WebView URL点击......);
view.loadUrl(URL);
返回true;
}
公共无效onPageFinished(web视图查看,字符串URL){
Log.i(TAG,加载完成URL:+网址);
如果(progressBar.isShowing()){
progressBar.dismiss();
}
}
公共无效onReceivedError(web视图来看,INT错误code,
字符串描述,字符串failingUrl){
Log.e(TAG,错误:+说明书+\ n错误code:
+错误code +\ñfailingUrl:+ failingUrl);
}
});
// mWebView.loadUrl(httppost.getURI()的toString());
mWebView.loadData(WEBDATA,text / html的,UTF-8);
mWebView.loadDataWithBaseURL(httppost.getURI()。toString()方法,WEBDATA,
text / html的,HTTP.UTF_8,NULL);
}赶上(例外前){
ex.printStackTrace();
}
}
同时点击继续抛出一个异常web视图按钮
11月2日至21日:42:38.539:E / webviewdatabase(2848):无法在setFormData
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):java.net.MalformedURLException:未知协议:约
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在java.net.URL中的< INIT>(URL.java:288)。
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在java.net.URL中的< INIT>(URL.java:157)。
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.WebViewDatabase.setFormData(WebViewDatabase.java:1032)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.BrowserFrame.loadStarted(BrowserFrame.java:384)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.JWebCoreJavaBridge.sharedTimerFired(本机方法)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.JWebCoreJavaBridge.fireSharedTimer(JWebCoreJavaBridge.java:91)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.JWebCoreJavaBridge.handleMessage(JWebCoreJavaBridge.java:108)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.os.Handler.dispatchMessage(Handler.java:99)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.os.Looper.loop(Looper.java:123)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在android.webkit.WebViewCore $ WebCoreThread.run(WebViewCore.java:673)
一十一月2日至21日:42:38.539:E / webviewdatabase(2848):在java.lang.Thread.run(Thread.java:1019)
一十一月2日至21日:42:41.324:E /缓存(2848):非法到期:星期六,2000年1月1日一点01分01秒格林尼治标准时间
解决方案
使用这样
的WebView的WebView =新的WebView(本);
的setContentView(web视图);
byte []的帖子= EncodingUtils.getBytes(postvariable =值放大器; nextvar =值2,BASE64);
webview.postUrl(http://www.geenie.nl/AnHeli/mobile/ranking/demo/index.php,后);
I'm attempting to connect to the page using an HTTP Post. I do an http post for creating a webview. i need to redirect to another page from the webview. But when the continue button is clicked exception is thrown .
My code is
public class ZHttpPostProjActivity extends Activity {
/** Called when the activity is first created. */
private WebView mWebView;
private ProgressDialog progressBar;
private static final String TAG = "ZHttpPostProjActivity";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.web_view);
mWebView = (WebView) findViewById(R.id.webview);
WebSettings webSettings = mWebView.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setDomStorageEnabled(true);
progressBar = ProgressDialog.show(ZHttpPostProjActivity.this, "",
"Loading...");
postData();
}
private final String URL_REGISTER = "https://www.paypal.com/checkout";
public void postData() {
BufferedReader bufferedReader = null;
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("username", "username"));
nameValuePairs.add(new BasicNameValuePair("password", "password"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(URL_REGISTER);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs,
HTTP.UTF_8));
HttpResponse response = httpclient.execute(httppost);
bufferedReader = new BufferedReader(new InputStreamReader(response
.getEntity().getContent()));
StringBuffer stringBuffer = new StringBuffer("");
String line = "";
String LineSeparator = System.getProperty("line.separator");
while ((line = bufferedReader.readLine()) != null) {
stringBuffer.append(line + LineSeparator);
}
bufferedReader.close();
String webData = stringBuffer.toString();
Log.i(TAG + "web data : ", webData);
// String webData = new
// BasicResponseHandler().handleResponse(response);
Log.i(TAG, "Httppost.getURI().toString(): "
+ httppost.getURI().toString());
mWebView.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Log.i(TAG, "Processing webview url click...");
view.loadUrl(url);
return true;
}
public void onPageFinished(WebView view, String url) {
Log.i(TAG, "Finished loading URL: " + url);
if (progressBar.isShowing()) {
progressBar.dismiss();
}
}
public void onReceivedError(WebView view, int errorCode,
String description, String failingUrl) {
Log.e(TAG, "Error: " + description + " \n errorCode: "
+ errorCode + "\n failingUrl: " + failingUrl);
}
});
// mWebView.loadUrl(httppost.getURI().toString());
mWebView.loadData(webData, "text/html", "UTF-8");
mWebView.loadDataWithBaseURL(httppost.getURI().toString(), webData,
"text/html", HTTP.UTF_8, null);
} catch (Exception ex) {
ex.printStackTrace();
}
}
While Clicking the continue button in the webview an exception is thrown
02-21 11:42:38.539: E/webviewdatabase(2848): Failed in setFormData
02-21 11:42:38.539: E/webviewdatabase(2848): java.net.MalformedURLException: Unknown protocol: about
02-21 11:42:38.539: E/webviewdatabase(2848): at java.net.URL.<init>(URL.java:288)
02-21 11:42:38.539: E/webviewdatabase(2848): at java.net.URL.<init>(URL.java:157)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.WebViewDatabase.setFormData(WebViewDatabase.java:1032)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.BrowserFrame.loadStarted(BrowserFrame.java:384)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.JWebCoreJavaBridge.sharedTimerFired(Native Method)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.JWebCoreJavaBridge.fireSharedTimer(JWebCoreJavaBridge.java:91)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.JWebCoreJavaBridge.handleMessage(JWebCoreJavaBridge.java:108)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.os.Handler.dispatchMessage(Handler.java:99)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.os.Looper.loop(Looper.java:123)
02-21 11:42:38.539: E/webviewdatabase(2848): at android.webkit.WebViewCore$WebCoreThread.run(WebViewCore.java:673)
02-21 11:42:38.539: E/webviewdatabase(2848): at java.lang.Thread.run(Thread.java:1019)
02-21 11:42:41.324: E/cache(2848): illegal expires: Sat, Jan 01 2000 01:01:01 GMT
解决方案
Use like this
WebView webview = new WebView(this);
setContentView(webview);
byte[] post = EncodingUtils.getBytes("postvariable=value&nextvar=value2", "BASE64");
webview.postUrl("http://www.geenie.nl/AnHeli/mobile/ranking/demo/index.php", post);
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