安卓 - 在登录后的WebView提取饼干 [英] Android - extracting cookies after login in webview

问题描述

我有一个web视图中打开一个网址的应用程序，用户必须再通过web视图登录到网站，并获得一次登录的Cookie。我在登陆后获取的Cookie的问题。

现在的问题是，我可以用android.webkit.CookieManager做到这一点，并输出所有cookie在一个单一的字符串。

不过，我想用一个cookie存储（如java.net.CookieStore）来实现它，所以我需要使用java.net.CookieManager。

我使用的是WebViewClient的onPageFinished（）中的以下code。我知道这个问题是打开一个新的连接，在这里我需要得到从当前页面的内容。我倒是AP preciate一些帮助，谢谢

  @覆盖
        公共无效onPageFinished（web视图查看，字符串URL）{

            Log.d（TAG，装货完毕：+网址）;

            CookieSyncManager syncManager = CookieSyncManager.createInstance（Main.this）;
            syncManager.sync（）;

            CookieManager经理=新CookieManager（）;
            manager.setCookiePolicy（CookiePolicy.ACCEPT_ALL）;
            CookieHandler.setDefault（经理）;

            尝试 {
                URL等等=新的网址（URL）;
                HttpURLConnection的CON =（HttpURLConnection类）blah.openConnection（）;
                readStream（con.getInputStream（））; //输出HTML
            }
            赶上（例外五）{
            }

            CookieStore的cookieJar = manager.getCookieStore（）;
            名单＆LT;的HttpCookie＆GT;饼干= cookieJar.getCookies（）;

            对于（的HttpCookie饼干：饼干）{
                Log.d（TAG，cookie的名称：+ cookie.getName（）的toString（））;
            }
        }
 

解决方案

您可以通过这种方式从web视图中提取所有的cookie当前的URL作为字符串：

  @覆盖
公共无效onPageFinished（web视图查看，字符串URL）{
    字符串饼干= CookieManager.getInstance（）的getCookie（URL）。
    Log.d（TAG，所有的字符串中的饼干：+饼干）;
}
 

I have an application that opens a url in a webview, the user must then login to a site through the webview and receives a cookie once logged in. I'm having problems getting cookies after login.

The problem is, I can achieve this using android.webkit.CookieManager, and output all cookies in a single string.

However, I want to achieve it using the a cookie store (as in java.net.CookieStore) so I need to be using java.net.CookieManager.

I'm using the following code within the onPageFinished() of a WebViewClient. I know the issue is with opening a new connection, where I need to be getting the content from the current page. I'd appreciate some help, thanks

        @Override
        public void onPageFinished(WebView view, String url){

            Log.d(TAG, "Finished loading: " + url);

            CookieSyncManager syncManager = CookieSyncManager.createInstance(Main.this);
            syncManager.sync();

            CookieManager manager = new CookieManager();
            manager.setCookiePolicy(CookiePolicy.ACCEPT_ALL);
            CookieHandler.setDefault(manager);

            try {
                URL blah = new URL(url);
                HttpURLConnection con = (HttpURLConnection) blah.openConnection();
                readStream(con.getInputStream()); // outputting html
            } 
            catch (Exception e) {
            }

            CookieStore cookieJar = manager.getCookieStore();
            List<HttpCookie> cookies = cookieJar.getCookies();

            for (HttpCookie cookie: cookies) {
                Log.d(TAG, "cookie name : "+cookie.getName().toString());
            }
        }

解决方案

You can extract all cookies current url by this way from webview as string:

@Override
public void onPageFinished(WebView view, String url){
    String cookies = CookieManager.getInstance().getCookie(url);
    Log.d(TAG, "All the cookies in a string:" + cookies);
}

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