如何检查，如果接收器被注册在安卓 [英] how to check if Receiver is registered in android

问题描述

我需要的，如果不是我如何检查它的任何方法来检查，如果我注册的接收器仍然是注册？

I need to check if my registered receiver is still registered if not how do i check it any methods?

推荐答案

我不知道该API提供了直接的API，如果你考虑的这个线程：

I am not sure the API provides directly an API, if you consider this thread:

我想知道同样的事情。
  在我来说，我有一个的BroadcastReceiver 执行调用   上下文＃unregisterReceiver（BroadcastReceiver的）传递自己作为处理其接收的意图后，ARG。
  有一个小的机会，接收器的的onReceive（上下文，意图）方法被调用   不止一次，因为它是注册多个 IntentFilters ，创造潜在的抛出：IllegalArgumentException 从<$ C被抛出$ C>上下文＃unregisterReceiver（BroadcastReceiver的）。

I was wondering the same thing.
In my case I have a BroadcastReceiver implementation that calls Context#unregisterReceiver(BroadcastReceiver) passing itself as the arg after handling the Intent that it receives.
There is a small chance that the receiver's onReceive(Context, Intent) method is called more than once, since it is registered with multiple IntentFilters, creating the potential for an IllegalArgumentException being thrown from Context#unregisterReceiver(BroadcastReceiver).

在我来说，我可以存储私人同步成员呼吁上下文＃unregisterReceiver（BroadcastReceiver的）前检查，但它会   如果API提供的检查方法，更清洁。

In my case I can store a private synchronized member to check before calling Context#unregisterReceiver(BroadcastReceiver), but it would be much cleaner if the API provided a check method.

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