Java计算String的SHA-1摘要的十六进制表示 [英] Java calculate hex representation of a SHA-1 digest of a String

问题描述

不幸的是，我收到了奇怪的答案。

我将字符串存储为：

  MessageDigest cript = MessageDigest.getInstance（SHA-1 ）; 
 cript.reset（）; 
 cript.update（userPass.getBytes（utf8））; 
 this.password = new String（cript.digest（））; 
  

我想要这样 - >

< - >0c05aa56405c447e6678b7f3127febde5c3a9238

而不是

aff - > V@ \这是因为cript.digest（）返回一个字节数组，这是因为cript.digest（）返回一个字节数组，你正试图打印出一个字符字符串。你想将它转换为可打印的Hex字符串。

=noreferrer> commons-codec库：

 字符串密码=新字符串（Hex.encodeHex（cript。 digest（）），
 CharSet.forName（UTF-8））; 
  

I'm storing the user password on the db as a sha1 hash.

Unfortunately I'm getting strange answers.

I'm storing the string as this:

MessageDigest cript = MessageDigest.getInstance("SHA-1");
              cript.reset();
              cript.update(userPass.getBytes("utf8"));
              this.password = new String(cript.digest());

I wanted something like this -->

aff --> "0c05aa56405c447e6678b7f3127febde5c3a9238"

rather than

aff --> �V@\D~fx����:�8

解决方案

This is happening because cript.digest() returns a byte array, which you're trying to print out as a character String. You want to convert it to a printable Hex String.

Easy solution: Use Apache's commons-codec library:

String password = new String(Hex.encodeHex(cript.digest()),
                             CharSet.forName("UTF-8"));

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