用十进制表示替换所有十六进制数字 [英] Replacing all Hex numbers with Decimal representation
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问题描述
我有一个字符串: string s =我最喜欢的数字是:42,0x42,24和0x24
有没有一种方法可以使用正则表达式将所有十六进制数字替换为它们的十进制表示形式?
对于上面的例子,我期望得到:我最喜欢的数字是:42,66,24和36$ c 正则表达式和转换 ):
String source =我最喜欢的号码是:42,0x42,24和0x24;
String result = Regex.Replace(source,@0x(\d | [af] | [AF])+,
(MatchEvaluator)(match => Convert。 ToInt32(match.Value,16).ToString()));
我假定所有的十六进制数字都是非负数和足够小为 int
。
I have a string: string s ="My Favorite numbers are: 42, 0x42, 24 and 0x24"
Is there a way using Regex to replace all hex numbers to their Decimal representation?
For the example above, I would expect to get: "My Favorite numbers are: 42, 66, 24 and 36"
.
解决方案
Try this (regular expression and conversion):
String source = "My Favorite numbers are: 42, 0x42, 24 and 0x24";
String result = Regex.Replace(source, @"0x(\d|[a-f]|[A-F])+",
(MatchEvaluator) (match => Convert.ToInt32(match.Value, 16).ToString()));
I've assumed that all the hex numbers are non-negative and small enough to be int
.
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