如何将（Char，Int）的列表转换为具有给定重复字符数的字符串？ [英] How to convert a list of (Char,Int) to a string with the given number of repeated chars?

问题描述

如何将 [（char，Int）] 转换为第二个组件中的Int字符串给出第一个组件中字符的重复次数？例如，输入 [（a，9），（b，10）] 应该给出 [aaaaaaaaa，bbbbbbbbbb] 作为输出。

How can I convert [(char,Int)] to a String of the Int in the second component gives the number of repetitions of the character in the first component? For example the input [(a,9),(b,10)] should give ["aaaaaaaaa","bbbbbbbbbb"] as output.

推荐答案

The facetious and horrible answer:

Prelude> let replignore ((_,x):[]) = [replicate x 'b']; replignore ((_,x):xs) = replicate x 'a' : replignore xs
Prelude> replignore [(a,9),(b,10)]
<interactive>:1:13: Not in scope: `a'
<interactive>:1:19: Not in scope: `b'
Prelude> let a = undefined
Prelude> let b = undefined
Prelude> replignore [(a,9),(b,10)]
["aaaaaaaaa","bbbbbbbbbb"]

但它并不完全符合规格，因为它在答案中包含引号。 ;）

But it didn't quite fit the specs since it includes the quotation marks in the answer. ;)

我的观点是，你需要引用你的 Char 和 String 文字。

My point is, you need quotes around your Char and String literals.

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