使用类型族和泛型来查找Id值 [英] Using type families and Generics to find an Id value

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问题描述

这个问题与这一个有关,我想避免从数据结构中提取 Id 值的样板文件,但是以类型安全的方式提取。



I'在这里重复问题的相关细节:假设你有一个类型 Id

  newtype Id = Id {_id :: Int} 

你想定义一个函数 getId 从至少包含一个 Id Id $ c $ value:

  class可识别的e其中
getId :: e - > Id

现在的问题是如何在类型安全的 strong>方式,同时避免使用泛型的样板在我的上一个问题我被指向类型族,特别是在此博客文章中描述。据我了解,这个想法是定义一个类型类 MkIdentifiable ,例如:

  class MakeIdentifiable(res :: Res)e其中
mkGetId :: Proxy res - > e - > Id

如果值的类型为 Res 仅当嵌套在其中的至少一个 Id 值时:

  data Crumbs = Here | L面包屑| R Crumbs 
数据Res = Found Crumbs | NotFound

然后,您可以定义:

 实例MakeIdentifiable(找到e)e =>可识别的e,其中
getId = mkGetId(Proxy :: Proxy(Found e))

现在问题是如何为 Res 定义一个与GHC.Generics类型相关的类型族( U1 K1 :*::+:)。



我试过以下内容:

  type family HasId e :: Res where 
HasId Id = Found Here
HasId((l:+:r)p)= Choose(HasId(lp))(HasId(rp))

$ b $ 选择就像前面提到的博客文章所定义的那样: / p>

  type family选择ef :: Res其中
选择(找到a)b =找到(L1 a)
选择a(找到b)=找到(R1 b)
选择ab =未找到

但是,这不会被编译为 HasId(lp)有类型 Res ,而是预期类型。

解决方案

您非常接近选择 typecheck。 L1 R1 (:+:)的构造函数, ,而不是面包屑。还有一个类型 GHC.Generics.R :: * ,它从隐藏了 R 构造函数。 Crumbs 在类型级别,但是您可以使用'R 来消除歧义(单引号是构造函数,双引号是类型构造函数)。



注释各种类型也是一种很好的做法,就像我们注释顶级函数的类型一样。



<$ p $ (e :: Res)(f :: Res):: Res其中
选择(找到a)b =找到('L a)
选择(找到b)=找到('R b)
选择NotFound NotFound = NotFound - 我不是重叠家庭的粉丝


This question is related to this one, where I wanted to avoid the boilerplate of extracting an Id value from a data structure, but in a type-safe manner.

I'll repeat the relevant details of the problem here: suppose you have a type Id:

newtype Id = Id { _id :: Int }

And you want to define a function getId that extracts this Id from any structure that contains at least one Id value:

class Identifiable e where
    getId :: e -> Id

Now the problem is how to define such a class in a type-safe manner, while at the same time avoiding the boilerplate using Generics.

In my previous question I was pointed to type families, and in particular to the ideas described in this blog post. As far as I understand the idea is to define a type-class MkIdentifiable such that:

class MakeIdentifiable (res :: Res) e where
    mkGetId :: Proxy res -> e -> Id

Where a value is of type Res only if there is at least one Id value that is nested inside of it:

data Crumbs = Here | L Crumbs | R Crumbs
data Res = Found Crumbs | NotFound

Then, it seems, one could define:

instance MakeIdentifiable (Found e) e => Identifiable e where
    getId = mkGetId (Proxy :: Proxy (Found e))

Now the question is how to define a type family for Res that is associated to the types of GHC.Generics (U1, K1, :*:, :+:).

I've tried the following:

type family HasId e :: Res where
    HasId Id = Found Here
    HasId ((l :+: r) p) = Choose (HasId (l p)) (HasId (r p))

Where Choose would be something like what is defined in the aforementioned blog post:

type family Choose e f :: Res where
    Choose (Found a) b = Found (L1 a)
    Choose a (Found b) = Found (R1 b)
    Choose a b = NotFound

But this won't compile as HasId (l p) has kind Res and a type is expected instead.

解决方案

You're pretty close to making Choose typecheck. L1 and R1 are constructors of (:+:), not Crumbs. There's also a type GHC.Generics.R :: * which hides the R constructor from Crumbs at the type level, but you can use 'R to disambiguate (singly-quoted names are constructors, doubly-quoted are type constructors).

It's also good practice to annotate kinds of types, much like we annotate types of toplevel functions.

type family Choose (e :: Res) (f :: Res) :: Res where
  Choose (Found a) b = Found ('L a)
  Choose a (Found b) = Found ('R b)
  Choose NotFound NotFound = NotFound  -- I'm not a fan of overlapping families

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