哈斯克尔：如何在日期和时间上打印秒数？ [英] Haskell: How to pretty print number of seconds as a date and time?

问题描述

我有一个整数值，即自Epoch以来的秒数。我可以将它输出为一个大整数，但我想将它显示为人类可读的日期和时间。

I have an integral value that is the number of seconds since the Epoch. I can output it as a big integer, but I want to show it as a human-readable date and time.

例如：

For example:

secToTimestamp :: Int32 -> [Char]

返回类似于：

2016-01-01 14:11:11

推荐答案

为了简化 时间 基于解决方案（因为时间是处理任何时间相关的事实模块）：

In the interests of having a simple time based solution (since time is the defacto module for manipulating anything time related):

import Data.Time.Clock.POSIX
import Data.Time.Format

secToTimestamp :: Int32 -> String
secToTimestamp = formatTime defaultTimeLocale "%F %X" . posixSecondsToUTCTime . fromIntegral

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