从uicolor的六角形颜色 [英] hex color from uicolor

问题描述

我在将uicolor转换为十六进制颜色时遇到了问题，这里是我发现的

  CGColorRef colorref = [[Colorview_ backgroundColor] CGColor]; 
 
 int numComponents = CGColorGetNumberOfComponents（colorref）; 
 
 if（numComponents == 4）{
 const CGFloat * components = CGColorGetComponents（colorref）; 
 
 int hexValue = 0xFF0000 * components [0] + 0xFF00 * components [1] + 0xFF * components [2]; 
 
 NSString * hexString = [NSString stringWithFormat：@＃％d，hexValue]; 
} 
  

这段代码给了我＃5576149（例如）hexString，看看有7个数字不是6，它不是一个十六进制颜色，任何帮助将不胜感激，thx。

NSString * hexString = [NSString stringWithFormat：@＃％d，hexValue];


您将其格式化为包含％d的数字

你想用十六进制格式化为％x或％X - 也许作为字符串％s我没有检查函数正在做什么以及 int hexValue 是持有

d或i有符号十进制整数392

x无符号十六进制整数7fa

X无符号十六进制整数（大写字母）7FA

i have a problem in converting uicolor to hex color, here what i found

CGColorRef colorref = [[Colorview_ backgroundColor] CGColor];

int numComponents = CGColorGetNumberOfComponents(colorref);

if (numComponents == 4) {
    const CGFloat *components = CGColorGetComponents(colorref);

    int hexValue = 0xFF0000*components[0] + 0xFF00*components[1] + 0xFF*components[2];

    NSString *hexString = [NSString stringWithFormat:@"#%d", hexValue];
}

this code is giving me #5576149 (for example) for hexString, us you see there are 7 digits not 6, it's not a hex color, any help will be appreciated, thx.

解决方案

NSString *hexString = [NSString stringWithFormat:@"#%d", hexValue];

You are formatting it as a digit with %d

You want to format it as hex with %x or %X -- maybe as string %s I didnt check what the function is doing and what int hexValue is holding

d or i Signed decimal integer 392

x Unsigned hexadecimal integer 7fa

X Unsigned hexadecimal integer (capital letters) 7FA

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