ios - 动态创建并显示unicode字符串 [英] ios - dynamically create and display unicode strings

问题描述

我有一个 UILabel ，我想在其中显示一个Unicode字符。以下工作：

I have a UILabel in which I want to display a Unicode character. The following works:

label.text = @"\U000025A0";

现在我想动态生成一个十进制数的Unicode字符，如下所示：

Now I want to dynamically generate the Unicode character from a decimal number as follows:

label.text = NSString stringWithFormat:@"\U%08x",9632];

Xcode编译器失败，出现以下错误：

Xcode compiler fails with the following error:

\U used with no following hex digits

是有一种方法可以将十进制数9632转换为Unicode，然后将其显示在 UILabel ？

Is there a way to convert the decimal number 9632 to Unicode and then display it in a UILabel?

推荐答案

我有同样的问题来显示entypo字体的特殊字符，所以我实现了我自己的 EntypoStringCreator 类（有一些SO的帮助）。这里是用于将unicode数字转换为nsstring的方法：

I had a same issue to display entypo Font special character, so I implemented my own EntypoStringCreator class (with some help from SO). Here are the method used to convert a unicode number to a nsstring:

.h

@interface EntypoStringCreator : NSObject

+(NSString *)stringForIcon:(UTF32Char)char32;

@end

.m

@implementation EntypoStringCreator


+(NSString *)stringForIcon:(UTF32Char)char32
{
    if ((char32 & 0xFFFF0000) != 0)
        return [self stringFromUTF32Char:char32];
    else
        return [self stringFromUTF16Char:(UTF16Char)(char32&0xFFFF)];
}

+(NSString *)stringFromUTF32Char:(UTF32Char)char32
{
    char32 -= 0x10000;
    unichar highSurrogate = (unichar)(char32 >> 10); // leave the top 10 bits
    highSurrogate += 0xD800;
    unichar lowSurrogate = char32 & 0x3FF; // leave the low 10 bits
    lowSurrogate += 0xDC00;
    return [NSString stringWithCharacters:(unichar[]){highSurrogate, lowSurrogate} length:2];
}

+(NSString *)stringFromUTF16Char:(UTF16Char)char16
{
    return [NSString stringWithCharacters:(unichar[]){char16} length:1];
}


@end

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