iOS - 字符串中单个字符的Unicode数字值 [英] iOS - Unicode numeric value of individual characters in a string

问题描述

对于iOS中的Objective-C：

For Objective-C in iOS:

如果我有一个字符串，如何读取单个字符的unicode数值？

If I have a string how could I read the unicode numeric value of an individual character?

例如，如果我的字符串是：Δ那个unicode字符是U + 0394，那么如何读取字符串，找出0394，然后创建一个新的字符串，那么新的字符串将是字符U + 0494或ҕ

For example if my string was: "∆" That unicode character is U+0394, so how could I read the string, figure out the "0394" then create a new string with say 100 added to that value, so the new string would be the character U+0494 or "ҕ"

谢谢！

推荐答案

首先，你的逻辑有谬误。 Δ+ 100！=ҕ。 Unicode以十六进制计算，因此Δ实际上等于小数中的 916 ，而不是 394 。因此， 0x0494 - 0x0394 = 0x0100 ，等于 256 。

First, there is a fallacy in your logic. ∆ + 100 != ҕ. Unicode is evaluated in base-16 (hex), so '∆' is actually equal to 916 in decimal, not 394. Thus, 0x0494 - 0x0394 = 0x0100, which equals 256.

考虑到这一点，你的代码应该看起来像这样：

With that in mind, your code should look something like this:

unichar delta = 0x0394;
unichar weirdB = delta + 0x0100;

NSString *deltaStr = [NSString stringWithCharacters:&delta length:1];
NSString *weirdBString = [NSString stringWithCharacters:&weirdB length:1]; 

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