检查十六进制字符串只包含十六进制有界值 [英] check hex string contains only hex bounded values

问题描述

如何检查给定的十六进制字符串只包含十六进制数字。是否有任何简单的方法或任何Java库的相同？我有字符串像01AF，我必须检查字符串只包含十六进制范围值，因为我现在正在做的是采取字符串，然后拆分字符串和然后将其转换为适当的格式，然后检查该值。有没有简单的方法呢？

How to check a given hex string contains only hex number. is there is any simple method or any java library for the same?i have string like "01AF" and i have to check string only contains hex range values,for that what i am doing now is take the string and then split the string and then converted it to appropriate format then make a check for that value.is there is any simple method for that?

推荐答案

try
{
    String hex = "AAA"
    int value = Integer.parseInt(hex, 16);  
    System.out.println("valid hex);
 }
 catch(NumberFormatException nfe)
 {
    // not a valid hex
    System.out.println("not a valid hex);
 }

如果十六进制字符串无效，将抛出NumberFormatException。

This will throw NumberFormatException if the hex string is invalid.

请参阅文档这里

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