如何在Hibernate中使用HAVING COUNT(*) [英] HOW to use HAVING COUNT(*) with hibernate
问题描述
我需要创建一个查询,并且需要 COUNT(*)
和 HAVING COUNT(*)= x
。
我使用的解决方法是使用 CustomProjection
类,我在某处下载。
这是我尝试实现的SQL:
$ p $ select count(* )as y0_,this_.ensayo_id as y1_ from Repeticiones this_
inner join Lineas linea1_ on this_.linea_id = linea1_.id
where this.pesoKGHA> 0.0 and this_.nroRepeticion = 1 and linea1_.id in 18,24)
group by this_.ensayo_id
count(*)= 2
这是代码,我使用 Projection
Hibernate类:
critRepeticion.setProjection(Projections.projectionList()
.add(Projections.groupProperty(ensayo))
.add(CustomProjections.groupByHaving(ensayo_id,Hibernate.LONG,COUNT ensayo_id)=+ String.valueOf(lineas.size()))
.ad d(Projections.rowCount())
);
错误是:
!STACK 0
java.lang.NullPointerException $ b $ org.hibernate.criterion.ProjectionList.toSqlString(ProjectionList.java:50)
org.hibernate.loader .criteria.CriteriaQueryTranslator.getSelect(CriteriaQueryTranslator.java:310)
位于org.hibernate.loader.criteria.CriteriaJoinWalker。< init>(CriteriaJoinWalker.java:71)
位于org.hibernate.loader。 criteria.CriteriaLoader。< init>(CriteriaLoader.java:67)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1550)
at org.hibernate.impl.CriteriaImpl.list (CriteriaImpl.java:283)
at ar.com.cse.cseagro.controller.RepeticionController.buscarEnsayo(RepeticionController.java:101)
如果我用 CustomProjections
类注释行,查询就可以工作,但我没有得到在SQL中具有COUNT(*)
过滤器...
基本上,查询尝试在master - detail中检索chema,所有主记录中的细节清单同时出现,比如你想知道哪些发票有两种产品,A和B。
这就是为什么如果我在 IN
子句中有3个项目,我需要使用 HAVING COUNT = 3
子句。
任何想法或建议?
此致,
我找到了问题所在。我将CusotmProjections类替换为:
.add(Projections.sqlGroupProjection(ensayo_id,groupBy,alias,types));
其中groupBy,别名和类型是:
String groupBy =ensayo_id+having+count(*)=+ String.valueOf(lineas.size());
String [] alias = new String [1];
Alias [0] =ensayo_id;
键入[] types = new Type [1];
类型[0] = Hibernate.INTEGER;
魔法在groupby String上。 -
I need to create a query and I need COUNT(*)
and HAVING COUNT(*) = x
.
I'm using a work around that uses the CustomProjection
class, that I downloaded somewhere.
This is the SQL that I try to achieve:
select count(*) as y0_, this_.ensayo_id as y1_ from Repeticiones this_
inner join Lineas linea1_ on this_.linea_id=linea1_.id
where this_.pesoKGHA>0.0 and this_.nroRepeticion=1 and linea1_.id in (18,24)
group by this_.ensayo_id
having count(*) = 2
This is the code, where I use the Projection
Hibernate class:
critRepeticion.setProjection(Projections.projectionList()
.add( Projections.groupProperty("ensayo") )
.add( CustomProjections.groupByHaving("ensayo_id",Hibernate.LONG,"COUNT(ensayo_id) = "+String.valueOf(lineas.size()))
.add( Projections.rowCount() )
);
The error is:
!STACK 0
java.lang.NullPointerException
at org.hibernate.criterion.ProjectionList.toSqlString(ProjectionList.java:50)
at org.hibernate.loader.criteria.CriteriaQueryTranslator.getSelect(CriteriaQueryTranslator.java:310)
at org.hibernate.loader.criteria.CriteriaJoinWalker.<init>(CriteriaJoinWalker.java:71)
at org.hibernate.loader.criteria.CriteriaLoader.<init>(CriteriaLoader.java:67)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1550)
at org.hibernate.impl.CriteriaImpl.list(CriteriaImpl.java:283)
at ar.com.cse.cseagro.controller.RepeticionController.buscarEnsayo(RepeticionController.java:101)
If I comment the line with CustomProjections
class, the query work, but I don't get the HAVING COUNT(*)
filter in the SQL ...
Basically the query try to retrieve, in a master - detail schema, all the master records where a list of details are simultaneously present, like if you want tho know "which invoices have both products, A and B".
That why if I got 3 items in the IN
clause, I need to use HAVING COUNT = 3
clause.
Any idea or suggestion? Best regards,
I figured out the problem. I replace CusotmProjections class, with:
.add( Projections.sqlGroupProjection("ensayo_id", groupBy , alias, types));
where groupBy, alias and types are:
String groupBy = "ensayo_id" + " having " + "count(*) = " + String.valueOf(lineas.size());
String[] alias = new String[1];
Alias[0] = "ensayo_id";
Type[] types = new Type[1];
types[0] = Hibernate.INTEGER;
and the magic is on groupby String. –
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