如何使用Spring 3配置JPA？ [英] How to get JPA configured with Spring 3?

问题描述

我一直在阅读spring的文档，但我必须说它有点令人困惑，给出了有关如何配置JPA的几种不同选项。

什么是最好的方法，以及如何获得JPA 2（与休眠）配置春天3？如果你有一个pom，web.xml，applicationContext.xml和任何所需的java代码的例子，请你也可以发布它。

谢谢！

解决方案

我使用EclipseLink，但配置必须非常相似。这里你有最重要的部分。

pom.xml：

  <依赖性> 
< groupId> org.springframework< / groupId> 
< artifactId> spring-orm< / artifactId> 
< version> $ {org.springframework-version}< / version> 
< /依赖关系> 
< dependency> 
< groupId> org.eclipse.persistence< / groupId> 
< artifactId> eclipselink< / artifactId> 
< version> 2.0.1< / version> 
< /依赖关系> 
< dependency> 
< groupId> javax.persistence< / groupId> 
< artifactId> javax.persistence< / artifactId> 
< version> 2.0.0< / version> 
< /依赖关系> 
  

persistence.xml：

 <？xml version =1.0encoding =UTF-8？> 
< persistence xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
 xsi：schemaLocation =http://java.sun.com/xml/ns /持久性
 http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd
 version =2.0xmlns =http://java.sun.com/xml/ NS /持久性> 
 
< persistence-unit name =persistenceUnittransaction-type =RESOURCE_LOCAL/> 
 
< /持久性> 
  

applicationContext-dao.xml：

 < bean id =entityManagerFactoryclass =org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean> 
< property name =persistenceXmlLocationvalue =classpath：persistence.xml/> 
< property name =persistenceUnitNamevalue =persistenceUnit/> 
< property name =dataSourceref =dataSource/> 
< property name =jpaPropertyMap> 
<道具> 
< prop key =eclipselink.weaving> false< / prop> 
< /道具> 
< / property> 
< / bean> 
 
< bean id =transactionManagerclass =org.springframework.orm.jpa.JpaTransactionManager> 
< property name =entityManagerFactoryref =entityManagerFactory/> 
< / bean> 
< tx：注解驱动的事务管理器=transactionManager/> 
  

User.java：

  @Entity 
 public class User {
 
 @Id 
 @GeneratedValue（strategy = GenerationType.SEQUENCE）
 private Integer id; 
 
私人字符串名称; 
 
 // Getters and setters 
 
} 
  

UserDao.java：

  @Repository 
 public class JpaUserDao implements UserDao {
 
 @ PersistenceContext 
 private EntityManager em; 
 
 @Override 
 public Item get（Integer id）{
 return em.find（User.class，id）; 
 
 
 $ / code $ / pre 
 $ b $ UserService.java：
 
 
  @Service 
 public class UserServiceImpl implements UserService {
 $ b $ @Autowired 
 private UserDao userDao; 
 
 @Transactional 
 @Override 
 public User getUser（Integer id）{
 return userDao.get（id）; 
} 
 
} 
  
希望它有帮助。
 
I have been reading spring's documentation, but I must say it is a bit confusing, giving several different option on how to configure JPA.

What is the best way, and how, to get JPA 2 (with hibernate) configured with spring 3? If you have an example of pom, web.xml, applicationContext.xml, and any needed java code, could you please kindly post it as well. 

thanks!
解决方案
I use EclipseLink, but configuration must be very similar. Here you have most important parts.

pom.xml:
    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-orm</artifactId>
        <version>${org.springframework-version}</version>
    </dependency>
    <dependency>
        <groupId>org.eclipse.persistence</groupId>
        <artifactId>eclipselink</artifactId>
        <version>2.0.1</version> 
    </dependency>
    <dependency> 
        <groupId>javax.persistence</groupId>
        <artifactId>javax.persistence</artifactId>
        <version>2.0.0</version>
    </dependency>
persistence.xml:
    <?xml version="1.0" encoding="UTF-8" ?>
    <persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence 
    http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
    version="2.0" xmlns="http://java.sun.com/xml/ns/persistence">

    <persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL" />

</persistence>
applicationContext-dao.xml:
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="persistenceXmlLocation" value="classpath:persistence.xml" />
    <property name="persistenceUnitName" value="persistenceUnit" /> 
    <property name="dataSource" ref="dataSource"/>
    <property name="jpaPropertyMap">
        <props>
            <prop key="eclipselink.weaving">false</prop>
        </props>
    </property>
</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager" />
User.java:
@Entity
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    private Integer id;

    private String name;

    // Getters and setters

}
UserDao.java:
@Repository
public class JpaUserDao implements UserDao {

    @PersistenceContext
    private EntityManager em;

    @Override
    public Item get(Integer id) {
        return em.find(User.class, id);
    }
}
UserService.java:
@Service 
public class UserServiceImpl implements UserService {

    @Autowired
    private UserDao userDao;

    @Transactional
    @Override
    public User getUser(Integer id) {
        return userDao.get(id);
    }

}
Hope it helps.

                        
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