Hibernate Criteria子查询 [英] Hibernate Criteria Subquery

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本文介绍了Hibernate Criteria子查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

  SELECT g.id FROM游戏g 
WHERE NOT EXISTS(
SELECT 1 FROM users_games ug WHERE ug.user_id = 1 AND g.id = ug.game_id)

这个想法是从不属于用户的游戏中获取ID。
我使用detachedCriteria尝试了10种不同的方法,但是我得到了Unknown entity:nullMappingException
代码应该如下所示:

  DetachedCriteria subquery = DetachedCriteria.forClass(UserGame.class,ug)
.add(Restrictions.eq(ug.user.id,1))
.add (Restrictions.eqProperty( ug.game.id, u.id));
DetachedCriteria criteria = DetachedCriteria.forClass(Game.class,g)
.add(Subqueries.notExists(subquery));

设定预测值只返回游戏的ID。



有什么想法?
我认为Hibernate在加入没有别名的查询时遇到了一些麻烦。
添加别名有效,但结果是错误的。

解决方案

您需要添加一个别名,如下所示:

  DetachedCriteria子查询= DetachedCriteria.forClass(UserGame.class,ug)
.addAlias(ug.user ,user)
.add(Restrictions.eq(user.id,1))
.addAlias(ug.game,game)
.add(限制.eqProperty( game.id, u.id));

这应该有所帮助


I need to do this SQL query with detachedCriteria:

SELECT g.id FROM games g
WHERE NOT EXISTS (
    SELECT 1 FROM users_games ug WHERE ug.user_id = 1 AND g.id = ug.game_id)

The idea is to get the ids from the games that aren't owned by the user. I tried like 10 different approaches with detachedCriteria but I get the "Unknown entity: null" MappingException The code should look like:

DetachedCriteria subquery = DetachedCriteria.forClass(UserGame.class, "ug")
   .add(Restrictions.eq("ug.user.id", 1))
   .add(Restrictions.eqProperty("ug.game.id","u.id"));
DetachedCriteria criteria = DetachedCriteria.forClass(Game.class, "g")
   .add(Subqueries.notExists(subquery));

Setting also the projections to return only the id of the games.

Any ideas? I think Hibernate has some trouble joining the queries with no alias. Adding alias works but the results are quite wrong.

解决方案

You need to add an alias, as follows:

DetachedCriteria subquery = DetachedCriteria.forClass(UserGame.class, "ug")
   .addAlias("ug.user", "user")
   .add(Restrictions.eq("user.id", 1))
   .addAlias("ug.game", "game")
   .add(Restrictions.eqProperty("game.id","u.id"));

That should help

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