Hibernate Criteria按子记录数排序 [英] Hibernate Criteria order by count of child records
问题描述
我有两类:新闻和评论,它们之间有一对多的关联。
我使用Hibernate Criteria从数据库中获取新闻。
session.createCriteria(News.class,n );
criteria.createAlias(n.comments,评论);
criteria.setProjection(Projections.projectionList()
.add(Projections.groupProperty(comments.id))
.add(Projections.count(comments.id)。as ( numberOfComments)));
criteria.addOrder(Order.desc(numberOfComments));
列表<新闻> news = criteria.list();
使用下面的代码,我得到的不是新闻列表,而是包含两个Long的对象列表在他们每个人。
我应该怎么做才能得到排序后的新闻对象列表?
我找到了答案问题在这里:
Hibernate Criteria API - 如何订购通过集合大小?
我添加了新的hibernate Order实现:
public class SizeOrder extends Order {
protected String propertyName;
protected boolean ascending;
protected SizeOrder(String propertyName,boolean ascending){
super(propertyName,ascending);
this.propertyName = propertyName;
this.ascending =升序;
}
$ b $ public String toSqlString(Criteria criteria,CriteriaQuery criteriaQuery)throws HibernateException {
String role = criteriaQuery.getEntityName(criteria,propertyName)+'。'+ criteriaQuery.getPropertyName( propertyName的);
QueryableCollection cp =(QueryableCollection)criteriaQuery.getFactory()。getCollectionPersister(role);
String [] fk = cp.getKeyColumnNames();
String [] pk =((Loadable)cp.getOwnerEntityPersister())
.getIdentifierColumnNames();
返回(select count(*)from+ cp.getTableName()+其中
+ new ConditionFragment()
.setTableAlias(
criteriaQuery.getSQLAlias(criteria, propertyName)
).setCondition(pk,fk)
.toFragmentString()+)
+(升序?asc:desc);
public static SizeOrder asc(String propertyName){
return new SizeOrder(propertyName,true);
public static SizeOrder desc(String propertyName){
return new SizeOrder(propertyName,false);
}
}
然后按照我的标准
criteria.addOrder(SizeOrder.desc(n.comments));
现在一切正常,
非常感谢大家:)
I have two classes: News and Comments with one-to-many association between them. I am using Hibernate Criteria to fetch news from database. I would like my news to be ordered by the count of its comments.
session.createCriteria(News.class, "n");
criteria.createAlias("n.comments", "comments");
criteria.setProjection(Projections.projectionList()
.add(Projections.groupProperty("comments.id"))
.add(Projections.count("comments.id").as("numberOfComments")));
criteria.addOrder(Order.desc("numberOfComments"));
List<News> news = criteria.list();
With the following code I'm getting not the list of news but the list of objects with two Long's in each of them. What should I do to get the list of sorted news objects?
I've found the answer to my question here: Hibernate Criteria API - how to order by collection size?
I've added the new hibernate Order implementation:
public class SizeOrder extends Order {
protected String propertyName;
protected boolean ascending;
protected SizeOrder(String propertyName, boolean ascending) {
super(propertyName, ascending);
this.propertyName = propertyName;
this.ascending = ascending;
}
public String toSqlString(Criteria criteria, CriteriaQuery criteriaQuery) throws HibernateException {
String role = criteriaQuery.getEntityName(criteria, propertyName) + '.' + criteriaQuery.getPropertyName(propertyName);
QueryableCollection cp = (QueryableCollection) criteriaQuery.getFactory().getCollectionPersister(role);
String[] fk = cp.getKeyColumnNames();
String[] pk = ((Loadable) cp.getOwnerEntityPersister())
.getIdentifierColumnNames();
return " (select count(*) from " + cp.getTableName() + " where "
+ new ConditionFragment()
.setTableAlias(
criteriaQuery.getSQLAlias(criteria, propertyName)
).setCondition(pk, fk)
.toFragmentString() + ") "
+ (ascending ? "asc" : "desc");
}
public static SizeOrder asc(String propertyName) {
return new SizeOrder(propertyName, true);
}
public static SizeOrder desc(String propertyName) {
return new SizeOrder(propertyName, false);
}
}
And then applied that to my criteria as
criteria.addOrder(SizeOrder.desc("n.comments"));
Now everything works fine, thanks everyone a lot :)
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