JavaFX + Hibernate(JPA)持久性+ Derby DB [英] JavaFX + Hibernate(JPA) persistence + Derby DB

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本文介绍了JavaFX + Hibernate(JPA)持久性+ Derby DB的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在开发一个Java桌面应用程序,并对使用JavaFX非常感兴趣。我打算使用MVC架构,因为我有一些Java EE和MVC模型的经验。



我想将数据存储在嵌入式derby数据库中并使用Hibernate作为持久层,但我找不到一篇关于用hibernate和JavaFX实现MVC的好教程。



我创建了持久性文件,但我不确定如何制作它与JavaFX一起工作。在Java EE中,我注入EJB服务或DAO,但由于我的应用程序没有连接服务器,我认为我不能这样做。

有人能解释我如何实现这个目标吗?可以一起使用它们吗?

解决方案

在我的最后一个JavaFX项目中,我在服务层下创建了一个DataBroker类,可以完成数据库中的所有CRUD操作。



示例:

  public class DataBroker {

private EntityManager em;

public DataBroker(){
init();


private void init(){
this.em = Persistence.createEntityManagerFactory(< NAME_OF_YOUR_PU>)。createEntityManager();
}

public Person saveOrUpdate(Person entity){
em.getTransaction()。begin();
T savedEntity = em.merge(entity);
em.getTransaction()。commit();
返回savedEntity;
}

public List< Person> getAllPersons(){
TypedQuery< Person> query = em.createNamedQuery(Person.GET_ALL,Person.class);
返回query.getResultList();
}

}

如果您只需要一个DataBroker实例,如果你需要一个实例池,创建一个池,你也许可以将它实现为Singleton。这是应用服务器的优点,他为你做这一切,你只需要注释你的类或成员。



我希望这可以帮到你。



编辑/更新
这里是EclipseLink 2.1的一个工作示例,但它只是持久性提供程序,所以它也可以用于Hibernate。



我创建了一个DataBroker,如上例所示实现我的IDataBroker接口并覆盖这些方法。



IDataBroker
$ b

  import de.professional_webworkx.crm.domain.Person; 
import java.util.List;


public interface IDateBroker {

public abstract void saveOrUpdate(Person person);
public abstract List< Person> getAllPersons();
public abstract Person getPersonById(int id);
public abstract Person getPersonByEmail(String email);
}

DataBroker - 并非每个方法都实现了.. 。

  import de.professional_webworkx.crm.domain.Person; 
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.Persistence;

/ **
*
* @author Patrick Ott< Patrick.Ott@professional-webworkx.de>
* @version 1.0
* /
public class DataBroker implements IDateBroker {

private EntityManager em;

public DataBroker(){
em = Persistence.createEntityManagerFactory(CRMPU)。createEntityManager();



$ b @Override
public void saveOrUpdate(Person person){
em.getTransaction()。begin();
em.merge(person);
em.getTransaction()。commit();
}

@Override
public List< Person> getAllPersons(){
抛出新的UnsupportedOperationException(还不支持。); //要更改生成方法的主体,请选择工具|模板。
}

@Override
public Person getPersonById(int id){
throw new UnsupportedOperationException(Not supported yet。); //要更改生成方法的主体,请选择工具|模板。
}

@Override
public Person getPersonByEmail(String email){
throw new UnsupportedOperationException(Not supported yet。); //要更改生成方法的主体,请选择工具|模板。
}


}

IPersonService接口

  import de.professional_webworkx.crm.domain.Person; 
import java.util.List;


public interface IPersonService {

void saveOrUpdate(Person person);
列表< Person> getAllPersons();
Person getPersonById(int id);
Person getPersonByEmail(String email);
}

PersonService

  import de.professional_webworkx.crm.databroker.DataBroker; 
导入de.professional_webworkx.crm.databroker.IDateBroker;
import de.professional_webworkx.crm.domain.Person;
import java.util.List;


公共类PersonService实现IPersonService {

私有IDateBroker代理;

public PersonService(){
broker = new DataBroker();
}

@Override
public void saveOrUpdate(Person person){
broker.saveOrUpdate(person);
}

@Override
public List< Person> getAllPersons(){
return broker.getAllPersons();
}

@Override
public Person getPersonById(int id){
return broker.getPersonById(id);
}

@Override
public Person getPersonByEmail(String email){
return broker.getPersonByEmail(email);


我们的Domain class Person

  import java.io.Serializable; 
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;


@Entity
@Table(name =person)
public class Person实现Serializable {

private long id;
private String firstName;
private String lastName;
私人字符串电子邮件;
$ b $ public Person(){
}

public Person(String firstName,String lastName,String eMail){
this.firstName = firstName;
this.lastName = lastName;
this.eMail =电子邮件;


$ b @Id
@GeneratedValue(strategy = GenerationType.AUTO)
public long getId(){
return id;
}


public void setId(long id){
this.id = id;


$ b @Size(min = 2,max = 255,message =输入2到255个字符!)
@Column(name = firstname)
@NotNull
public String getFirstName(){
return firstName;
}


public void setFirstName(String firstName){
this.firstName = firstName;


$ b @Column(name =lastname)
@NotNull
public String getLastName(){
return lastName;
}


public void setLastName(String lastName){
this.lastName = lastName;
}


@NotNull
public String geteMail(){
return eMail;
}


public void seteMail(String eMail){
this.eMail = eMail;
}


}

FXMLController class

  import de.professional_webworkx.crm.business.IPersonService; 
import de.professional_webworkx.crm.business.PersonService;
import de.professional_webworkx.crm.domain.Person;
import java.net.URL;
import java.util.ResourceBundle;
import javafx.event.ActionEvent;
import javafx.fxml.FXML;
import javafx.fxml.Initializable;
import javafx.scene.control.Label;

公共类FXMLController实现了可初始化{

私有IPersonService服务;

@FXML
私有标签标签;

@FXML
private void handleButtonAction(ActionEvent event){
Person p = new Person(Demo,User,demo@example.com);
service.saveOrUpdate(p);

$ b @Override
public void initialize(URL url,ResourceBundle rb){
//获取PersonService的实例
service = new PersonService( );





最后但并非最不重要的MainApp以启动应用程序。

  import javafx.application.Application; 
import static javafx.application.Application.launch;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;


public class MainApp extends Application {
$ b $ @Override
public void start(Stage stage)throws Exception {
Parent root = FXMLLoader .load(的getClass()的getResource( / FXML / Scene.fxml)。);

场景场景=新场景(root);
scene.getStylesheets()。add(/ styles / Styles.css);

stage.setTitle(JavaFX and Maven);
stage.setScene(scene);
stage.show();
}


public static void main(String [] args){
launch(args);
}

}

这是一个标准的Maven JavaFX项目使用Netbeans 8创建。如果需要,我可以将源文件上传到GitHub或其他东西。



数据库表将在第一次提交时创建,因为我在persistence.xml文件,即可以从文件中看到的Schema Generation

 <?xml version =1.0encoding = UTF-8 >?; 
< persistence version =2.1xmlns =http://xmlns.jcp.org/xml/ns/persistencexmlns:xsi =http://www.w3.org/2001/XMLSchema-实例xsi:schemaLocation =http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd\">
< persistence-unit name =CRMPUtransaction-type =RESOURCE_LOCAL>
< provider> org.eclipse.persistence.jpa.PersistenceProvider< / provider>
< class> de.professional_webworkx.crm.domain.Person< / class>
<属性>
< property name =javax.persistence.jdbc.urlvalue =jdbc:mysql:// localhost:3306 / exampleDb?zeroDateTimeBehavior = convertToNull/>
< property name =javax.persistence.jdbc.uservalue =user/>
< property name =javax.persistence.jdbc.drivervalue =com.mysql.jdbc.Driver/>
< property name =javax.persistence.jdbc.passwordvalue =pass/>
< property name =javax.persistence.schema-generation.database.actionvalue =create/>
< / properties>
< / persistence-unit>
< /余辉>

所以我希望这可以帮助您创建您的项目。



Patrick

I'm developing a Java desktop application and was really interested in use JavaFX. I'm planning to use an MVC architecture because I have had some experience with Java EE and the MVC model.

I want to store data in a embedded derby database and use Hibernate as persistence layer but I can't find a great tutorial about implementing MVC with hibernate and JavaFX.

I have created the persistence file but I am not sure how to make it work with JavaFX. In Java EE I inject EJB services or DAOs but since my app is not server connected I think I can't do that.

Can someone explain me how to achieve that? It is possible to use them together?

解决方案

In one of my last JavaFX Projects, i created under my Service Layer a DataBroker class, which could do all the CRUD Operations on the Database.

Example:

public class DataBroker {

    private EntityManager em;

    public DataBroker() {
        init();
    }

    private void init() {
        this.em = Persistence.createEntityManagerFactory("<NAME_OF_YOUR_PU>").createEntityManager();
    }

    public Person saveOrUpdate(Person entity) {
        em.getTransaction().begin();
        T savedEntity = em.merge(entity);
        em.getTransaction().commit();
        return savedEntity;
    }

    public List<Person> getAllPersons() {
        TypedQuery<Person> query = em.createNamedQuery(Person.GET_ALL, Person.class);
        return query.getResultList();
    }

}

If you only need one DataBroker Instance, you maybe can realize it as a Singleton, if you need a Pool of Instances, create a Pool. This is the advantage of a Application Server, he does this all for you and you only have to annotate your Classes or Members.

I hope this will help you.

EDIT / UPDATE Here is a working example with EclipseLink 2.1, but it is only the Persistence Provider, so it works also with Hibernate.

I created a DataBroker like in the above example which implements my IDataBroker Interface and overrides the methods.

IDataBroker

import de.professional_webworkx.crm.domain.Person;
import java.util.List;


public interface IDateBroker {

    public abstract void saveOrUpdate(Person person);
    public abstract List<Person> getAllPersons();
    public abstract Person getPersonById(int id);
    public abstract Person getPersonByEmail(String email);
}

DataBroker - not every method is implemented...

import de.professional_webworkx.crm.domain.Person;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.Persistence;

/**
 *
 * @author Patrick Ott <Patrick.Ott@professional-webworkx.de>
 * @version 1.0
 */
public class DataBroker implements IDateBroker {

    private EntityManager em;

    public DataBroker() {
        em = Persistence.createEntityManagerFactory("CRMPU").createEntityManager();
    }



    @Override
    public void saveOrUpdate(Person person) {
        em.getTransaction().begin();
        em.merge(person);
        em.getTransaction().commit();
    }

    @Override
    public List<Person> getAllPersons() {
        throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }

    @Override
    public Person getPersonById(int id) {
        throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }

    @Override
    public Person getPersonByEmail(String email) {
        throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }


}

IPersonService Interface

import de.professional_webworkx.crm.domain.Person;
import java.util.List;


public interface IPersonService {

    void saveOrUpdate(Person person);
    List<Person> getAllPersons();
    Person getPersonById(int id);
    Person getPersonByEmail(String email);
}

PersonService

import de.professional_webworkx.crm.databroker.DataBroker;
import de.professional_webworkx.crm.databroker.IDateBroker;
import de.professional_webworkx.crm.domain.Person;
import java.util.List;


public class PersonService implements IPersonService {

    private IDateBroker broker;

    public PersonService() {
        broker = new DataBroker();
    }

    @Override
    public void saveOrUpdate(Person person) {
        broker.saveOrUpdate(person);
    }

    @Override
    public List<Person> getAllPersons() {
        return broker.getAllPersons();
    }

    @Override
    public Person getPersonById(int id) {
        return broker.getPersonById(id);
    }

    @Override
    public Person getPersonByEmail(String email) {
        return broker.getPersonByEmail(email);
    }
}

Our Domain class Person

import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;


@Entity
@Table(name = "person")
public class Person implements Serializable {

    private long id;
    private String firstName;
    private String lastName;
    private String eMail;

    public Person() {
    }

    public Person(String firstName, String lastName, String eMail) {
        this.firstName = firstName;
        this.lastName = lastName;
        this.eMail = eMail;
    }


    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    public long getId() {
        return id;
    }


    public void setId(long id) {
        this.id = id;
    }


    @Size(min = 2, max = 255, message = "Enter between 2 and 255 characters!")
    @Column(name = "firstname")
    @NotNull
    public String getFirstName() {
        return firstName;
    }


    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }


    @Column(name = "lastname")
    @NotNull
    public String getLastName() {
        return lastName;
    }


    public void setLastName(String lastName) {
        this.lastName = lastName;
    }


    @NotNull
    public String geteMail() {
        return eMail;
    }


    public void seteMail(String eMail) {
        this.eMail = eMail;
    }


}

The FXMLController class

import de.professional_webworkx.crm.business.IPersonService;
import de.professional_webworkx.crm.business.PersonService;
import de.professional_webworkx.crm.domain.Person;
import java.net.URL;
import java.util.ResourceBundle;
import javafx.event.ActionEvent;
import javafx.fxml.FXML;
import javafx.fxml.Initializable;
import javafx.scene.control.Label;

public class FXMLController implements Initializable {

    private IPersonService service;

    @FXML
    private Label label;

    @FXML
    private void handleButtonAction(ActionEvent event) {
        Person p = new Person("Demo", "User", "demo@example.com");
        service.saveOrUpdate(p);
    }

    @Override
    public void initialize(URL url, ResourceBundle rb) {
        // get an instance of PersonService
        service = new PersonService();

    }    
}

And last but not least the MainApp to start the Application.

import javafx.application.Application;
import static javafx.application.Application.launch;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;


public class MainApp extends Application {

    @Override
    public void start(Stage stage) throws Exception {
        Parent root = FXMLLoader.load(getClass().getResource("/fxml/Scene.fxml"));

        Scene scene = new Scene(root);
        scene.getStylesheets().add("/styles/Styles.css");

        stage.setTitle("JavaFX and Maven");
        stage.setScene(scene);
        stage.show();
    }


    public static void main(String[] args) {
        launch(args);
    }

}

This is a standard Maven JavaFX Project created with Netbeans 8. If necessary i can upload the Sources to GitHub or something..

The Database Table will be created with the first commit, because i set up in the persistence.xml file, that Schema Generation as you can see from the file

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
  <persistence-unit name="CRMPU" transaction-type="RESOURCE_LOCAL">
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
    <class>de.professional_webworkx.crm.domain.Person</class>
    <properties>
      <property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/exampleDb?zeroDateTimeBehavior=convertToNull"/>
      <property name="javax.persistence.jdbc.user" value="user"/>
      <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/>
      <property name="javax.persistence.jdbc.password" value="pass"/>
      <property name="javax.persistence.schema-generation.database.action" value="create"/>
    </properties>
  </persistence-unit>
</persistence>

So i hope this will help you to create your project.

Patrick

这篇关于JavaFX + Hibernate(JPA)持久性+ Derby DB的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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