JPA 2.0按照条款api的顺序选择/子查询 [英] JPA 2.0 subselect / subquery in order by clause with criteria api

查看:130
本文介绍了JPA 2.0按照条款api的顺序选择/子查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用JPA 2.0标准API来通过子选择来构建order by子句。我知道你可以在普通的SQL中做到这一点,但它可以与标准API映射?有人可以给一个代码示例吗?

I want to use JPA 2.0 criteria api to build the order by clause with a subselect. I know that you can do that in plain SQL but can it be mapped with criteria api? Can someone please give a code example?

示例:

Example:

Order(name, address) // table1

OrderPriority(address, priority) // table2 priority by address

select o from Order o order by (select p.priority from OrderPriority p where 
p.address = o.address)


推荐答案

Criteria API查询被转换为JPQL,并且显然JPQL中不支持顺序中的子查询子句。

Criteria API queries are converted to JPQL and apparently subqueries in the order by clause are not supported in JPQL.

类似的StackOverflow答案可以在这里找到。

Similar StackOverflow answer can be found here.

这篇关于JPA 2.0按照条款api的顺序选择/子查询的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆