弹簧数据jpa @Entity属性未找到异常 [英] spring data jpa @Entity property not found exception

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问题描述

我对spring-data-jpa很陌生，目前正试图用hibernate实现。我已经按照教程！为此，我目前面临启动应用程序本身的问题。
在启动过程中，我收到以下异常：

 原因：org.springframework.data.mapping.PropertyReferenceException：No在org.springframework.data.mapping.PropertyPath中找到类型为com.adaptris.dashboard.customer.Customer 
的物业客户。< init>（PropertyPath.java:74）$ or 
 at org.springframework.data .mapping.PropertyPath.create（PropertyPath.java:326）
 at org.springframework.data.mapping.PropertyPath.create（PropertyPath.java:352）
 at org.springframework.data.mapping.PropertyPath .create（PropertyPath.java:306）
 at org.springframework.data.mapping.PropertyPath.from（PropertyPath.java:270）
 at org.springframework.data.mapping.PropertyPath.from（PropertyPath .java：244）
在org.springframework.data.repository.query.parser.Part。< init>（Part.java:73）
 at org.springframework.data.repository.query。 parser.PartTree $ OrPart。< init>（PartTree.java:180）
 at org.springframework.data.repository.query.parser.PartTree $ Predica te.buildTree（PartTree.java:260）
 at org.springframework.data.repository.query.parser.PartTree $ Predicate。< init>（PartTree.java:240）
 at org.springframework .data.repository.query.parser.PartTree。< init>（PartTree.java:71）
 at org.springframework.data.jpa.repository.query.PartTreeJpaQuery。< init>（PartTreeJpaQuery.java： 57）
 at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy $ CreateQueryLookupStrategy.resolveQuery（JpaQueryLookupStrategy.java:90）
 at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy $ CreateIfNotFoundQueryLookupStrategy.resolveQuery（JpaQueryLookupStrategy.java:162）维持在org.springframework.data org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy $ AbstractQueryLookupStrategy.resolveQuery（JpaQueryLookupStrategy.java:68）
 
。 repository.core.support.RepositoryFactorySupport $ QueryExecutorMethodInterceptor。< init>（RepositoryFactorySupport.java:280）
 at org.springframework.data.re在org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject（RepositoryFactoryBeanSupport.java:125）
 
。 springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject（RepositoryFactoryBeanSupport.java:41）
 at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.doGetObjectFromFactoryBean（FactoryBeanRegistrySupport.java:142）

客户是我的域名类，注解为 

  @Entity（name =customer）

我想这是试图连接到数据库并获取我实际配置的客户表。这里是我的spring-config： 

 < tx：annotation-driven transaction-manager =transactionManager/> 
 <！ - 激活Spring Data JPA存储库支持 - > 
< jpa：repositories base-package =com.adaptris.dashboard.customer/> 
 
 <！ - 声明具有池化功能的数据源 - > 
< bean id =jpaDataSourceclass =com.mchange.v2.c3p0.ComboPooledDataSource
 destroy-method =closep：driverClass =$ {app.jdbc.driverClassName} 
p：jdbcUrl =$ {app.jdbc.url}p：user =$ {app.jdbc.username}p：password =$ {app.jdbc.password}
p： acquireIncrement =5p：idleConnectionTestPeriod =60p：maxPoolSize =100
p：maxStatements =50p：minPoolSize =10/> 
 
 <！ - 声明一个JPA entityManagerFactory  - > 
< bean id =entityManagerFactory
 class =org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean
p：persistenceXmlLocation =classpath *：META-INF / persistence.xml
p：persistenceUnitName =hibernatePersistenceUnitp：dataSource-ref =jpaDataSource
p：jpaVendorAdapter-ref =hibernateVendor/> 
 
 <！ - 指定我们的ORM供应商 - > 
  class =org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter
 p：showSql =false/> 
 
 <！ - 声明一个事务管理器 - > 
< bean id =transactionManagerclass =org.springframework.orm.jpa.JpaTransactionManager
 p：entityManagerFactory-ref =entityManagerFactory/>

而DB是运行的MYSQL。以下是属性： 

 ＃数据库属性
 app.jdbc.driverClassName = com.mysql.jdbc.Driver 
 app.jdbc.url = jdbc\：mysql\：// Mallik-PC / adaptrisschema 
 app.jdbc.username = dbuser 
 app.jdbc.password = dbpassword

请帮我解决这个问题!!

解决方案

听起来像您为Domain类指定的Repository接口包含 findXXX 方法，而 XXX 不是您的Domain类的属性。



示例： public interface UserRepository扩展CrudRepository< User，String> {

/ **
*按名称查找用户。
*
* @param name要查找的用户的名称。
* @返回具有给定名称的用户。
* /
public User findByName（String name）;
}

而你的Domain类看起来像这样并且错过了name属性：

  @Entity 
 public class User {
 private String firstname; 
私人字符串姓氏; 
 //这里没有私人字符串名称！ 
 ...

在您的特定示例中，它看起来像添加了一个 findByCustomer（Customer customer）方法到您的Repository接口（可能称为 CustomerRepository ）。您不需要该方法，因为Spring Data for JPA会自动为您生成 findOne（< PrimaryKeyClass> id）方法，您可以使用 @Id 您的Domain类 Customer 作为参数。


I am new to the spring-data-jpa and am currently trying to implement with hibernate. I've followed the tutorial! for this and am currently facing issues starting the application itself. I get the following exception during startup:

 Caused by: org.springframework.data.mapping.PropertyReferenceException: No property customer found for type com.adaptris.dashboard.customer.Customer
at org.springframework.data.mapping.PropertyPath.<init>(PropertyPath.java:74)
at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:326)
at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:352)
at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:306)
at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:270)
at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:244)
at org.springframework.data.repository.query.parser.Part.<init>(Part.java:73)
at org.springframework.data.repository.query.parser.PartTree$OrPart.<init>(PartTree.java:180)
at org.springframework.data.repository.query.parser.PartTree$Predicate.buildTree(PartTree.java:260)
at org.springframework.data.repository.query.parser.PartTree$Predicate.<init>(PartTree.java:240)
at org.springframework.data.repository.query.parser.PartTree.<init>(PartTree.java:71)
at org.springframework.data.jpa.repository.query.PartTreeJpaQuery.<init>(PartTreeJpaQuery.java:57)
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:90)
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateIfNotFoundQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:162)
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$AbstractQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:68)
at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.<init>(RepositoryFactorySupport.java:280)
at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:148)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:125)
at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:41)
at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.doGetObjectFromFactoryBean(FactoryBeanRegistrySupport.java:142)

Customer is my domain class annotated with 

@Entity(name = "customer")

And I suppose it is trying to connect to the DB and fetch the customer table which I've actually configured. Here is my spring-config:

<tx:annotation-driven transaction-manager="transactionManager" />
<!-- Activate Spring Data JPA repository support -->
<jpa:repositories base-package="com.adaptris.dashboard.customer" />

    <!-- Declare a datasource that has pooling capabilities -->
<bean id="jpaDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
    destroy-method="close" p:driverClass="${app.jdbc.driverClassName}"
    p:jdbcUrl="${app.jdbc.url}" p:user="${app.jdbc.username}" p:password="${app.jdbc.password}"
    p:acquireIncrement="5" p:idleConnectionTestPeriod="60" p:maxPoolSize="100"
    p:maxStatements="50" p:minPoolSize="10" />

<!-- Declare a JPA entityManagerFactory -->
<bean id="entityManagerFactory"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
    p:persistenceXmlLocation="classpath*:META-INF/persistence.xml"
    p:persistenceUnitName="hibernatePersistenceUnit" p:dataSource-ref="jpaDataSource"
    p:jpaVendorAdapter-ref="hibernateVendor" />

<!-- Specify our ORM vendor -->
<bean id="hibernateVendor"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"
    p:showSql="false" />

<!-- Declare a transaction manager -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
    p:entityManagerFactory-ref="entityManagerFactory" />

And the DB is MYSQL which is running. Following are the properties:

# database properties
app.jdbc.driverClassName=com.mysql.jdbc.Driver
app.jdbc.url=jdbc\:mysql\://Mallik-PC/adaptrisschema
app.jdbc.username=dbuser
app.jdbc.password=dbpassword

Please help me out in getting out of this issue!!

解决方案

Sounds like the Repository interface you have specified for your Domain class contains a findXXX method whereas XXX is not a property of your Domain class.

Example:

public interface UserRepository extends CrudRepository<User, String> {

    /**
     * Finds a user by name.
     * 
     * @param name The name of the User to find.
     * @return The User with the given name.
     */
    public User findByName(String name);
}

And your Domain class looks like this and misses the "name" property:

@Entity
public class User {
    private String firstname;
    private String lastname;
    // No "private String name" in here!
    ... 
}

In your particular example it looks like you added a findByCustomer(Customer customer) method to your Repository interface (probably called something like CustomerRepository). You don't need that method as a findOne(<PrimaryKeyClass> id) method is automatically generated for you by Spring Data for JPA and you can just call it with the @Id of your Domain class Customer as a parameter.

这篇关于弹簧数据jpa @Entity属性未找到异常的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！

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